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Message
You have 8 apparently identical balls, but one is heavier than the others
Posted on 10/16/17 at 7:30 pm
Posted on 10/16/17 at 7:30 pm
and you have a balance scale with which to weigh the balls
What is the fewest number of times you can use the scale to determine which is the heavier and how do you do it?
What is the fewest number of times you can use the scale to determine which is the heavier and how do you do it?
Posted on 10/16/17 at 7:30 pm to Masterag
I've only got two balls. Why do you have 8?
Posted on 10/16/17 at 7:31 pm to Masterag
4 and 4
Take the heavier side split 2 and 2
Take the heavier side and split 1 and 1
So 3 times
Take the heavier side split 2 and 2
Take the heavier side and split 1 and 1
So 3 times
This post was edited on 10/16/17 at 7:32 pm
Posted on 10/16/17 at 7:31 pm to Masterag
4 v 4
2 v 2
1 v 1
3 times.
Damn walruses
2 v 2
1 v 1
3 times.
Damn walruses
This post was edited on 10/16/17 at 7:32 pm
Posted on 10/16/17 at 7:32 pm to Masterag
quote:
You have 8 apparently identical balls, but one is heavier than the others
You should probably get that checked out
Posted on 10/16/17 at 7:32 pm to Masterag
Of course an aggie fan would be interested in balls.
This post was edited on 10/16/17 at 7:33 pm
Posted on 10/16/17 at 7:33 pm to Masterag
1 if you guess the right ball to begin with and use it to outweigh another
3 if you don’t start out by a lucky guess
Initial weigh in (4-4)
Split heavier side into 2-2
Split still heavier side into 1-1 to determine winner
ETA: I concede to the person who said/explained 2 below.
3 if you don’t start out by a lucky guess
Initial weigh in (4-4)
Split heavier side into 2-2
Split still heavier side into 1-1 to determine winner
ETA: I concede to the person who said/explained 2 below.
This post was edited on 10/17/17 at 8:51 am
Posted on 10/16/17 at 7:33 pm to Masterag
Four?
4 > 4
3 > 3
2 > 2
1 > 1 found the heaviest, probably not the answer though
Edit: I was close
4 > 4
3 > 3
2 > 2
1 > 1 found the heaviest, probably not the answer though
Edit: I was close
This post was edited on 10/16/17 at 7:34 pm
Posted on 10/16/17 at 7:34 pm to Masterag
The correct answer is 2 times.
3 x 3.
If they are equal, then the heavier ball is in the remaining 2, put them side by side.
If they are not equal, take 2 from the heavier side and put them side by side. If equal, heavier ball is the remaining one. Otherwise, heavier ball is obvious.
Answer = 2.
3 x 3.
If they are equal, then the heavier ball is in the remaining 2, put them side by side.
If they are not equal, take 2 from the heavier side and put them side by side. If equal, heavier ball is the remaining one. Otherwise, heavier ball is obvious.
Answer = 2.
Posted on 10/16/17 at 7:34 pm to Masterag
Just drop them all from a ladder and see which one hits first.
Posted on 10/16/17 at 7:35 pm to Masterag
quote:
What is the fewest number of times you can use the scale to determine which is the heavier and how do you do it?
The fewest? Once if you guess correctly.
Posted on 10/16/17 at 7:37 pm to Masterag
the fewest??? one time and a lucky guess.
Posted on 10/16/17 at 7:37 pm to Masterag
I've had this on an exam before. I was the only one in class to get it correct. The answer is 288
Posted on 10/16/17 at 7:37 pm to TheWalrus
I admire your flipper control. Or do you use your tusks?
Let me sing the song of your people... Goo Goo g'joob
Let me sing the song of your people... Goo Goo g'joob
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