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re: You have 8 apparently identical balls, but one is heavier than the others
Posted on 10/16/17 at 9:16 pm to beerJeep
Posted on 10/16/17 at 9:16 pm to beerJeep
quote:
4 v 4
2 v 2
1 v 1
3 times.
Damn walruses
If you are lucky - 2
Do 2 v 2 - if you succeed it's 2, if they are equal, do 2 v 2 again
ETA: of course the real answer is starting with 3 v 3... Saw the above answer and wanted to just respond to it to make it more efficient
This post was edited on 10/16/17 at 9:20 pm
0
Posted on 10/16/17 at 9:38 pm to Masterag
2
3 x 3
If they are equal, weigh the other 2.
If they aren't equal, take 2 from the heavy side and weigh them.
3 x 3
If they are equal, weigh the other 2.
If they aren't equal, take 2 from the heavy side and weigh them.
This post was edited on 10/16/17 at 9:39 pm
Posted on 10/16/17 at 9:43 pm to PearlJam
One.
Add the balls one at a time. Whenever a side is uneven in weight after adding a ball you know which was heavier.
Add the balls one at a time. Whenever a side is uneven in weight after adding a ball you know which was heavier.
Posted on 10/16/17 at 9:46 pm to Brosef Stalin
Imagine the load that you could shoot with 8 balls.
Posted on 10/16/17 at 11:10 pm to Masterag
quote:
What is the fewest number of times you can use the scale to determine which is the heavier
If you want better answers, work on your question.
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