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Started By
Message
re: Solve this OT
Posted on 7/23/18 at 9:48 am to theunknownknight
Posted on 7/23/18 at 9:48 am to theunknownknight
Common sense answer - 50%
Academic retarded answer - 67%
Academic retarded answer - 67%
0
Posted on 7/23/18 at 9:48 am to CoeJ
quote:
66.7% - you know that the box with two silvers is eliminated, leaving only one possible silver ball out of 3.
Another way to look at it is to realize there's a 2/3 chance your hand is in the box with two golds.
Posted on 7/23/18 at 9:49 am to PearlJam
quote:
Wrong. You are selecting out of 2 boxes. 1 will have a silver ball and the other will have a gold ball. The chances are 50/50.
Wronger. If you have selected a gold ball. The other box will have EITHER. 2 gold balls or 1 silver ball.
2/3 = 66.7%
Posted on 7/23/18 at 9:50 am to ThatMakesSense
quote:Yes, but because you have grabbed a gold ball, one box is eliminated. You know the one you picked either has 2 gold balls or 1 gold 1 silver. The chance is between 2 boxes at that point.
It clearly states the same box
Posted on 7/23/18 at 9:50 am to 50_Tiger
2/3
You’ve eliminated the 2 silvers and it’s more likely that the box you’ve drawn from has 2 gold than 1 gold and 1 silver. 3 balls left, 2 are gold.
You’ve eliminated the 2 silvers and it’s more likely that the box you’ve drawn from has 2 gold than 1 gold and 1 silver. 3 balls left, 2 are gold.
Posted on 7/23/18 at 9:50 am to CoeJ
quote:it isn't a choice between balls, but boxes.
EITHER. 2 gold balls or 1 silver ball.
Posted on 7/23/18 at 9:50 am to 50_Tiger
Some idiots up in here
Posted on 7/23/18 at 9:51 am to 50_Tiger
quote:
Exactly. The 67% folks are throwing the third box out of the equation without accounting for it.
Because the 3rd box is irrelevant.
This is an old problem just like the Monty Hall. The answer is definitively 2/3.
Posted on 7/23/18 at 9:51 am to 50_Tiger
quote:
Exactly. The 67% folks are throwing the third box out of the equation without accounting for it.
Right. Because one of the boxes has 0 gold balls, once I choose a gold ball I know I'm not picking out of the box there contains 2 silver balls.
I'm either in 2G Or 1G and 1S...4 balls to start, 1 G picked...3 balls left..2G, 1S...2/3. You did it, McClane.
This post was edited on 7/23/18 at 9:52 am
Posted on 7/23/18 at 9:51 am to CoeJ
You have three boxes. 66% of picking right box with gold in it.
One box has a S in it, which holds a 50% value of getting the G within that box.
The other has GG or 100% chance.
One box has a S in it, which holds a 50% value of getting the G within that box.
The other has GG or 100% chance.
Posted on 7/23/18 at 9:51 am to 50_Tiger
quote:
Exactly. The 67% folks are throwing the third box out of the equation without accounting for it.
You don't have to account for it. Assuming you are aware of the box arrangements and the problem doesn't state otherwise...
Once you pull a gold ball, you don't have to account for a box that you know with 100% certainty that you don't have.
Posted on 7/23/18 at 9:52 am to TH03
quote:
Because the 3rd box is irrelevant
How can you say this? You cannot look into the boxes.
Posted on 7/23/18 at 9:52 am to ThatMakesSense
quote:
I'm either in 2G Or 1G and 1S...4 balls to start, 1 G picked...3 balls left..2G, 1S...2/3. You did it, McClane.
NOOOOOOOOOOOOOOOOOOOOOOOOOOO!!!!
You have a gold ball in your hand, so the box either has 1 gold ball or 1 silver ball left in it. 50% chance.
This post was edited on 7/23/18 at 9:53 am
Posted on 7/23/18 at 9:53 am to 50_Tiger
quote:
Exactly. The 67% folks are throwing the third box out of the equation without accounting for it.
No, the 67% folks are not taking into account the gold ball they picked up and somehow think the other gold ball plays into it.....
There’s only 1 ball left in the box you selected (which is one of the first two)....there’s either a silver or gold ball left in the box you have. 1/2 it’s gold. 50% chance
Posted on 7/23/18 at 9:53 am to IT_Dawg
Google says 67% is the right answer.
Posted on 7/23/18 at 9:53 am to 50_Tiger
Once you pick a gold ball, you eliminated the all silver. It’s no longer about 6 balls, it’s about the 3 remaining.
Posted on 7/23/18 at 9:53 am to 50_Tiger
How are people NOT coming up with 50?
This is pretty straight forward with no gotcha or ambiguity
ETA: Forgot a NOT in there
This is pretty straight forward with no gotcha or ambiguity
ETA: Forgot a NOT in there
This post was edited on 7/23/18 at 10:02 am
Posted on 7/23/18 at 9:54 am to guedeaux
quote:
You have a gold ball in your hand, so the box either has 1 gold ball or 1 silver ball left in it. 50% chance.
Idiot.
Posted on 7/23/18 at 9:54 am to 50_Tiger
quote:
You cannot look into the boxes.
Seriously? I don’t need to. I’ve picked a gold ball. I know without a doubt my second pick IN THE SAME BOX (per the instructions) will not be out of the 3rd box with all silver.
Posted on 7/23/18 at 9:55 am to memphis tiger
quote:
I guess if you pick a gold ball then that rules out the box with 2 silver balls.
So the box was either the one with 2 gold or 1 gold and 1 silver.
So you know you are starting with 3 golds and one silver and you just picked one gold. You have left 3 balls, 2 gold and 1 silver. So you odds of picking a gold ball next are roughly 67%.
I think, anyway.
Almost.
Silver ball box gone.
So you have 2 boxes left. If its the 2 gold box, there's 1 gold left. If its the silver/gold box, there's 1 silver left.
Its 50%.
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