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Million dollar unsolved math problems
Posted on 6/25/22 at 11:37 pm
Posted on 6/25/22 at 11:37 pm
Millennium Prize Problems
The Riemann hypothesis (the Riemann zeta function has non-trivial zeroes at negative even integers and complex numbers with real part 1/2) seems simple enough, so I might give that a shot.
Proving P = NP might also be fun. People will be sweating about their encrypted information.
quote:
The Millennium Prize Problems are seven well-known mathematical problems selected by the Clay Mathematics Institute in 2000. The Clay Institute has pledged a US$1 million prize for the correct solution of any of the problems. To date, the only Millennium Prize problem to have been solved is the Poincaré conjecture. The Clay Institute awarded their monetary prize to Russian mathematician Grigori Perelman in 2010. However, he declined the award for not also being offered to Richard S. Hamilton, upon whose work Perelman built. The remaining six unsolved problems are the Birch and Swinnerton-Dyer conjecture, Hodge conjecture, Navier–Stokes existence and smoothness, P versus NP problem, Riemann hypothesis, and Yang–Mills existence and mass gap.
The Riemann hypothesis (the Riemann zeta function has non-trivial zeroes at negative even integers and complex numbers with real part 1/2) seems simple enough, so I might give that a shot.
Proving P = NP might also be fun. People will be sweating about their encrypted information.
Posted on 6/25/22 at 11:39 pm to UndercoverBryologist
quote:
Proving P = NP might also be fun.
Good fricking luck
Posted on 6/25/22 at 11:39 pm to UndercoverBryologist
The answer obviously is 350
Posted on 6/25/22 at 11:46 pm to Sao
quote:
PEMDAS.
?x^2 dx/dy = (x/3)^3 + C
Edit: Damn, TD doesn’t recognize the integral symbol...but we can have 30 abortion threads.
This post was edited on 6/25/22 at 11:48 pm
Posted on 6/26/22 at 12:17 am to UndercoverBryologist
quote:
Proving P = NP might also be fun.
Where is my $1M prize?
Posted on 6/26/22 at 3:16 am to UndercoverBryologist
quote:
The Riemann hypothesis (the Riemann zeta function has non-trivial zeroes at negative even integers and complex numbers with real part 1/2) seems simple enough
Never change OT
Posted on 6/26/22 at 4:24 am to UndercoverBryologist
quote:
Proving P = NP might also be fun.
N = 1
Posted on 6/26/22 at 5:50 am to UndercoverBryologist
Carry the 1
It will set you free
It will set you free
Posted on 6/26/22 at 6:01 am to UndercoverBryologist
If no one has solved it, how do they know what the real answers are?
Posted on 6/26/22 at 8:06 am to UndercoverBryologist
quote:
US$1 million prize for the correct solution of any of the problems
Not worth my time to look for the T-84
Posted on 6/26/22 at 8:09 am to UndercoverBryologist
quote:
The Riemann hypothesis (the Riemann zeta function has non-trivial zeroes at negative even integers and complex numbers with real part 1/2) seems simple enough, so I might give that a shot.

Posted on 6/26/22 at 8:12 am to Scruffy
quote:
If no one has solved it, how do they know what the real answers are?
They don't. They hypothesize what the answers are based on the answers they get when they solve with different parameters. Now they want to prove it fits the hypothesis for all parameters.
Posted on 6/26/22 at 8:15 am to UndercoverBryologist
Update: I made a major breakthrough at 4:30 am this morning on P vs. NP.
It occurred to me if I could write an equation describing “polynomial” time, and the re-arrange it, it’s essentially a diophantine elliptical equation.
As Wiles & Taylor (1995) demonstrated, all elliptical equations are modular. It’s now my interest to see if a non-polynomial mode of time has similar modularity.
I’ll keep people posted.
It occurred to me if I could write an equation describing “polynomial” time, and the re-arrange it, it’s essentially a diophantine elliptical equation.
As Wiles & Taylor (1995) demonstrated, all elliptical equations are modular. It’s now my interest to see if a non-polynomial mode of time has similar modularity.
I’ll keep people posted.
Posted on 6/26/22 at 8:20 am to UndercoverBryologist
quote:
essentially a diophantine elliptical equation.
There is your error, my friend. If it's only ESSENTIALLY a diophantine elliptical, it cannot be assumed to behave as a true diophantine equation in the general case.
Sorry.
Posted on 6/26/22 at 8:26 am to UndercoverBryologist
Do any of those involve an airplane on a treadmill?
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