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Posted on 3/7/21 at 5:17 pm to moontigr
In all seriousness, just break the first design down into right triangles and squares. They give you a hint in the picture.
For the second one it appears that the design is to scale on the grid and each grid square is 1cm^2, so you can count your way through it. They appear to give you all the hypotenuses (hypoteni? Lol)
The third and fourth questions are relevant to the two designs, just assume that you’re going to print them on a shirt.
For the second one it appears that the design is to scale on the grid and each grid square is 1cm^2, so you can count your way through it. They appear to give you all the hypotenuses (hypoteni? Lol)
The third and fourth questions are relevant to the two designs, just assume that you’re going to print them on a shirt.
Posted on 3/7/21 at 5:18 pm to RockinDood
Why is this shite in centimeters? What school is this?
Posted on 3/7/21 at 5:20 pm to Nado Jenkins83
quote:
Why is this shite in centimeters?
Because they're indoctrinating our children to embrace non-freedom loving units.
Posted on 3/7/21 at 5:20 pm to TigerstuckinMS
Figures. fricking commies.
Posted on 3/7/21 at 5:44 pm to moontigr
That is actually a good project. With a few mathematical rules, your son can figure out every bit of that. It is just an exercise in organization, and when done,you tabulate all of the totals.
Posted on 3/7/21 at 5:46 pm to moontigr
Come on man, at worst you should be able to add up squares and triangles
Posted on 3/7/21 at 5:50 pm to moontigr
I dropped out of high school my junior year but I scored a 29 on the ACT for the math section.
You already have the lenghts of all sides, you just have to sum them up. You have 8 times the side of the pointy bits, and 4 times the side of the octagon, so that would be 8*7.28cm + 4*4cm = 74,24cm
Now the area is a bit harder. The trick is to divide the area into easier shapes until you have a shape with an area you know the formula of. You have to find the area of the octagon and the area of the triangles on the sides. Let's begin by the easiest, the triangles.
You can use the general formula of the area of a triangle, base*height/2. On the left triangle you have the height (7cm), and the base is a side of the octagon. All sides of the octagon are the same lenght, 4cm. So one side triangle has an area of 4*7/2 = 14cm².
Finally the hardest part, the octagon. This time we have to devide it further. The idea is to sketch all the lines similar to the 9,7cm and the 2,8cm ones. You should have a kind of tic-tac-toe with the corners missing. From there you can calculate the areas of the 4 corner triangles (right-angled triangles, so (side1*side2)/2 using the side forming the right angle). You have the area of the central square which has a side of 4cm. And finally you have 4 rectangles on the sides, with one side of lenght 2.8 and one the same lenght as the square. Then you sum all theses areas to get the area of the octagon. I find 78,48cm².
Finally you sum the area of the octagon and of the 4 side triangles, and... bam.
You already have the lenghts of all sides, you just have to sum them up. You have 8 times the side of the pointy bits, and 4 times the side of the octagon, so that would be 8*7.28cm + 4*4cm = 74,24cm
Now the area is a bit harder. The trick is to divide the area into easier shapes until you have a shape with an area you know the formula of. You have to find the area of the octagon and the area of the triangles on the sides. Let's begin by the easiest, the triangles.
You can use the general formula of the area of a triangle, base*height/2. On the left triangle you have the height (7cm), and the base is a side of the octagon. All sides of the octagon are the same lenght, 4cm. So one side triangle has an area of 4*7/2 = 14cm².
Finally the hardest part, the octagon. This time we have to devide it further. The idea is to sketch all the lines similar to the 9,7cm and the 2,8cm ones. You should have a kind of tic-tac-toe with the corners missing. From there you can calculate the areas of the 4 corner triangles (right-angled triangles, so (side1*side2)/2 using the side forming the right angle). You have the area of the central square which has a side of 4cm. And finally you have 4 rectangles on the sides, with one side of lenght 2.8 and one the same lenght as the square. Then you sum all theses areas to get the area of the octagon. I find 78,48cm².
Finally you sum the area of the octagon and of the 4 side triangles, and... bam.
Posted on 3/7/21 at 5:51 pm to Gaston
quote:Wha???
I’m not doing 5th grade homework while I sit at a restaurant bar and watch golf.
Volvo doesn’t offer this option???
Posted on 3/7/21 at 6:23 pm to moontigr
Where did the 90.24 for the perimeter come from in the first drawing? It looks like it was provided for you but either I’m missing something or that’s the wrong answer.
Posted on 3/7/21 at 6:33 pm to nctiger71
Just start by breaking down the length of every side. Then you can literally just use google for the calculation of you don't know the formulas for the area.
Posted on 3/7/21 at 6:36 pm to moontigr
I have absolutely no idea why I clicked on this thread. I suck at math.
Posted on 3/7/21 at 6:41 pm to Ssubba
I calculate the perimeter of the first image to be 74.24 (7.28 X 8 + 4 X 4 = 74.24); but the answer shown is 90.24. It looks like the 90.24 was provided because it is typed. But, IDK, maybe the OP typed it.
And there appears to be a coordinate error in the 2nd drawing too.
And there appears to be a coordinate error in the 2nd drawing too.
Posted on 3/7/21 at 6:45 pm to nctiger71
The 90.24 was my son’s answer, which was incorrect.
We have the star figured out, just need the rocketship
We have the star figured out, just need the rocketship
Posted on 3/7/21 at 6:46 pm to moontigr
quote:
Mathematicians, your help is needed
Posted on 3/7/21 at 6:49 pm to moontigr
quote:
We have the star figured out, just need the rocketship
You still do?
ETA: I’ll work it out if you need.
This post was edited on 3/7/21 at 6:57 pm
Posted on 3/7/21 at 6:59 pm to Byrdybyrd05
quote:
Thanks for reminding me that I’m dreading when my son has to do this kind of math soon
review on your own time.
start using wolfram alpha once a week.
I ran into it junior year high school.
darling genius asked for help first time. shes drumming her fingers while I'm thinking, "how does this work?".
Posted on 3/7/21 at 7:06 pm to moontigr
Ok, there is not a coordinate error in the rocket ship. I counted from the wrong place.
Posted on 3/7/21 at 7:32 pm to moontigr
Is this a troll or is the OP for real?
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