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Started By
Message
re: Funtime - Solve this simple math problem
Posted on 4/17/21 at 5:33 pm to Pelican fan99
Posted on 4/17/21 at 5:33 pm to Pelican fan99
quote:
How tf are you even supposed to be able to tell the clock hands moved? Whoever created this needs to be shot in the face
Yeah this is some gay shite
0
Posted on 4/17/21 at 7:35 pm to DomincDecoco
(no message)
This post was edited on 5/1/21 at 8:22 am
Posted on 4/17/21 at 7:36 pm to DomincDecoco
25
Posted on 4/17/21 at 7:38 pm to RB10
Damn common core has failed most of y’all.
Posted on 4/17/21 at 8:21 pm to DomincDecoco
7
Posted on 4/17/21 at 8:23 pm to DomincDecoco
10..... a fricking 10....
Posted on 4/17/21 at 8:23 pm to DomincDecoco
1x10 = 10
10+ 1 + 3 = 14
10+ 1 + 3 = 14
This post was edited on 4/17/21 at 8:25 pm
Posted on 4/17/21 at 8:28 pm to ItNeverRains
This is not a math problem. It’s like a fricking find the hidden object game.
Posted on 4/17/21 at 9:06 pm to DomincDecoco
5x10= fiddy
Posted on 4/17/21 at 9:27 pm to DomincDecoco
Not enough information to solve. You have to make assumptions that have no underpinnings.
Equation 1: each cookie with 10 chips is worth 10
Equation 2: one cookie with 10 chips plus 2 pairs of bananas equals 14. Each pair of bananas is worth 2.
Equation 3: one pair of bananas plus 2 clocks at the 3 o clock position equals 8. Each clock at the 3 o clock position is worth 3.
Equation 4: a clock at the 2 o clock position (?) plus 2 single bananas plus a cookie with 7 chips. We have no way of knowing what these icons represent.
Before you say “well if a pair of bananas is worth 2, then a single banana is worth one” consider this—77 is worth 77 ones. Is 7 worth half as many ones as 77? Or only 1/11 of the ones? Is 10 half of 1010? The answer to all of those questions is yes depending on your baseline definitions
There is no agreed upon value for any of the icons in the final equation. There is no way to intuit the values. You can make a guess and argue your case about what each represents, but there isn’t any evidence that will tell us the correct answer.
It could be 10 it could be 542. We have no way of knowing.
Equation 1: each cookie with 10 chips is worth 10
Equation 2: one cookie with 10 chips plus 2 pairs of bananas equals 14. Each pair of bananas is worth 2.
Equation 3: one pair of bananas plus 2 clocks at the 3 o clock position equals 8. Each clock at the 3 o clock position is worth 3.
Equation 4: a clock at the 2 o clock position (?) plus 2 single bananas plus a cookie with 7 chips. We have no way of knowing what these icons represent.
Before you say “well if a pair of bananas is worth 2, then a single banana is worth one” consider this—77 is worth 77 ones. Is 7 worth half as many ones as 77? Or only 1/11 of the ones? Is 10 half of 1010? The answer to all of those questions is yes depending on your baseline definitions
There is no agreed upon value for any of the icons in the final equation. There is no way to intuit the values. You can make a guess and argue your case about what each represents, but there isn’t any evidence that will tell us the correct answer.
It could be 10 it could be 542. We have no way of knowing.
Posted on 4/17/21 at 9:31 pm to Lsuhoohoo
quote:
14-(c=10)= 4/2 pair of banana = 2. We've established the value of a single banana is 1.
Have we? Is 1 worth half of 11? Surely one 1 would be worth half of a pair of 1s. We don’t know if the bananas are placeholders in the tens digits or not.
What if each banana is worth sqrt(2)? Two square roots of 2 adjacent to each other would certainly evaluate to 2.
This post was edited on 4/17/21 at 9:43 pm
Posted on 4/17/21 at 9:37 pm to DomincDecoco
Check the time, count the bananas, count the chips.
2+1 + 1*7 = 10
2+1 + 1*7 = 10
Posted on 4/17/21 at 9:39 pm to DomincDecoco
I’m these are always so stupid. But I think I got 10.
Posted on 4/17/21 at 9:40 pm to Rouge
quote:
It is not about the cookies. It is about the number of chips in each cookie
How do you know the value of each cookie f(c) is simply equal to the # of chips (c) in the cookie? If that were the case, the equation would be f(c)=c. And a cookie with 7 chips would be worth 7.
But what if f(c)=100/c? In this case a cookie with 10 chips would still be worth 10. But a cookie with 7 chips would be 100/7. That’s a much different number.
The point is we have no way of determining the value of any of the images in the final equation
Posted on 4/17/21 at 10:06 pm to DomincDecoco
I think its indeterminate.
How are we to assume a 10 chip cookie is valued at 10, thus a 7 chip cookie must be valued at 7?
Maybe weight was involved and the first line, each cookie weighs 10 ounces. How are we to know the weight of the cookie in the last equation?
Maybe the clock has other meanings other than just the time.
How are we to assume a 10 chip cookie is valued at 10, thus a 7 chip cookie must be valued at 7?
Maybe weight was involved and the first line, each cookie weighs 10 ounces. How are we to know the weight of the cookie in the last equation?
Maybe the clock has other meanings other than just the time.
Posted on 4/17/21 at 10:13 pm to DomincDecoco
What if I told you that 80=50? You’d say I was stupid. But what if the LHS was hex and the RHS was dec? Then 80=50.
We don’t know what counting system the icons are using so we cannot know.
We don’t know what counting system the icons are using so we cannot know.
Posted on 4/17/21 at 11:36 pm to DomincDecoco
25
2 o'clock + 1 banana + (1 banana x 7 chocolate chips) = 10
First time I did not pay attention to number of banana's, chips or time on clock.
2 o'clock + 1 banana + (1 banana x 7 chocolate chips) = 10
First time I did not pay attention to number of banana's, chips or time on clock.
This post was edited on 4/17/21 at 11:40 pm
Posted on 4/17/21 at 11:43 pm to DomincDecoco
10 Look at the chips on the cookie
This post was edited on 4/17/21 at 11:45 pm
Posted on 4/17/21 at 11:46 pm to DomincDecoco
17
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