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Started By
Message
re: Could your wife or girlfriend solve this?
Posted on 2/14/25 at 10:45 am to collegefootballisbroken
Posted on 2/14/25 at 10:45 am to collegefootballisbroken
quote:
here’s literally nothing in your life as a grown up that will require you to know this unless you intentionally choose a job or task that requires you to know this.
Wrong. This is just a problem of knowing enough algebra to create an equation purely based in "x" and solve for "x". You have 3 triangles. The full triangle, and the little triangle. Sides of the triangle can be defined by "x" or "x" + 20 or 5. The hypotenuse of the two smaller triangles adds to the larger triangle. So you can now define the hypotenuse by "x" using the Pythagorean theorem. Then solve for "x". Almost anything requires the understanding of basic Algebra. If you don't know it, someone in your business does. The less you truly know, the more expendable you are. So yes, you maybe don't need to know it (I do personally), but at some point you should defintely know how to do this if you graduated high school.
0
Posted on 2/14/25 at 10:46 am to anc
My 12 year old could probably do it.
My wife? Absolutely not. I’m sure she knew how at some point.
I guess my DNA is tainted. I’ll let her know.
Thanks OP for the impending divorce.
My wife? Absolutely not. I’m sure she knew how at some point.
I guess my DNA is tainted. I’ll let her know.
Thanks OP for the impending divorce.
This post was edited on 2/14/25 at 10:47 am
Posted on 2/14/25 at 10:50 am to collegefootballisbroken
quote:ackshully - the Twitter link in OP is trying to slam women that don’t remember how to do this
This is some stupid person who thinks he’s superior because he remembers something most people don’t.
When in fact most people don’t. So don’t date dumb women even if you yourself are dumb.
Let’s hate on women
Posted on 2/14/25 at 10:52 am to anc
Simple solution
This post was edited on 2/14/25 at 11:05 am
Posted on 2/14/25 at 10:53 am to anc
Pretty easy.
Posted on 2/14/25 at 10:54 am to Bazzatcha
quote:that’s your wife’s or girlfriend’s work?
Simple solution
Posted on 2/14/25 at 10:55 am to GreenRockTiger
Hell no... she cooks and cleans, I calculate.
Posted on 2/14/25 at 10:56 am to castorinho
Yours doesn't count, because where you drew 5 is longer than where you drew 20.
Signed,
SFP or Mingo or Lester
Signed,
SFP or Mingo or Lester
Posted on 2/14/25 at 10:56 am to anc
100
Posted on 2/14/25 at 10:57 am to anc
No way in hell. I married a purty one, not a nerdy one. 
Posted on 2/14/25 at 10:57 am to Bazzatcha
quote:and apparently can’t read
I calculate.
Posted on 2/14/25 at 10:57 am to castorinho
quote:
Pretty easy.
Once i see it in that format I agree, but there’s really no reason for me have remembered that.
I think Section 179 depreciation or knowing what is considered a real property improvement for sales tax is in Louisiana is remedial, you almost certainly don’t.
Posted on 2/14/25 at 10:58 am to anc
288
Posted on 2/14/25 at 10:58 am to anc
This isn’t what I look for in a wife.
You have to use tangent (opposite / adjacent). And the fact that the two sides of the square are equal, we can use X to represent the length of all 4 sides of the square
The tangent of the smaller triangle is X/5. The tangent of the bigger triangle is 20/X.
Solve for X: X/5 = 20/X.
X is 10 (each side of the square). The area is 100.
Again, who actually cares if your wife can solve this?!
You have to use tangent (opposite / adjacent). And the fact that the two sides of the square are equal, we can use X to represent the length of all 4 sides of the square
The tangent of the smaller triangle is X/5. The tangent of the bigger triangle is 20/X.
Solve for X: X/5 = 20/X.
X is 10 (each side of the square). The area is 100.
Again, who actually cares if your wife can solve this?!
Posted on 2/14/25 at 10:58 am to castorinho
You don't have to use trig.
Just use similar triangles.
(20+a)/(5+a)=20/a
Solve for a^2 which is the area of the square.
Just use similar triangles.
(20+a)/(5+a)=20/a
Solve for a^2 which is the area of the square.
Posted on 2/14/25 at 10:59 am to anc
3
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5
0
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5
0
Posted on 2/14/25 at 10:59 am to anc
The lack of a right angle symbol is killing me
Posted on 2/14/25 at 11:04 am to anc
It’s impossible for a woman to solve this because they don’t have a penis to use to measure the square.
Posted on 2/14/25 at 11:05 am to Mingo Was His NameO
quote:You don't even need the Pythagorean theorem, you just have to know that all 3 triangles (the whole outer one and the two smaller inner ones) are all proportionately the same, given that we know the square *is* in fact a square.
I generally know that a square is the same on all sides so both sides of what missing are the same. You’d also use the Pythagorean theorem to solve it
So if x is a side of the square, we know that:
x/5 = 20/x
x^2 = 100
x = 10
So the area of the square is 100.
We can double check our answer in a roundabout way using similarly simple math. Let's figure the area of the big triangle if the square is 10x10.
20+10 = 30
5 + 10 = 15
30 * 15 = 450
450 / 2 = 225 is the area of the big triangle
Now subtract the areas of the two smaller triangles:
20*10 = 200 / 2 = 100
5 * 10 = 50 / 2 = 25
And 225 - (100 + 25) = 100
So we are left with the area of the square, our answer is right.
Any other value for the sides of the square do not work. Let's try 8, for example:
20+8 = 28
5 + 8 = 13
28 * 13 = 364
364 / 2 = 182 is the area of the big triangle
Subtract the two smaller triangles:
20*8 = 160 / 2 = 80
5 * 8 = 40 / 2 = 20
And 182 - (80+20) = 82
This result of 82 square units remaining for the square is *not* what we want, which would be 8 * 8 = 64. The length of the square's sides cannot be 8.
Posted on 2/14/25 at 11:06 am to anc
quote:
Could your wife or girlfriend solve this?
My wife is a chief risk officer at a international financial technology company and she couldn't solve this.
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