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re: Brainteaser/Riddle Thread
Posted on 12/16/19 at 1:37 pm to mark65mc
Posted on 12/16/19 at 1:37 pm to mark65mc
quote:again... you dont know if the odd man id heavier or lighter. you weight 3 on each side first and you can eliminate half.
One side will weigh more than the other. That narrows the field by half.
0
Posted on 12/16/19 at 1:37 pm to yankeeundercover
Posted on 12/16/19 at 1:38 pm to yankeeundercover
You put 6 men on either side of the seesaw. Now you have it narrowed down to 6 men. You pair the 6 men into twos and weigh two of the groups. If the seesaw is level, you use your last weigh for the 2 that weren’t on the seesaw. If it tips when you do the 2nd weigh you use the 3rd weigh to determine final outcome.
Posted on 12/16/19 at 1:39 pm to fr33manator
quote:
You pile 3 men on each side, for a total of 6.
I’d they are equal, then the other group is the one with the different weight
Then take those who were lighter/heavier, and take an extra and sit 2 on each side.
Then take the side that is lighter/heavier and 1 on each side
You’ll have your answer
This is the only answer. The only way the 6, 3, then 2 would work is if you know the odd man out is heavier or lighter than the rest.
Posted on 12/16/19 at 1:39 pm to Powerman
quote:quote:
weigh 6 on each side
This is the dumbest first move you can possibly make
No new information is garnered
Other than eliminating half the field, right?
ETA: Yea I'm dumb
This post was edited on 12/16/19 at 1:54 pm
Posted on 12/16/19 at 1:41 pm to Roll Tide Ravens
quote:
a dime and a nickel. One of them is a nickel
Posted on 12/16/19 at 1:42 pm to LNCHBOX
quote:
Other than eliminating half the field, right?
But you might eliminate the wrong half. As a couple have said, you don't know if the oddball is a fatty or the other 11 are.
I did it wrong in my head at first too. Then I saw what ramrod was saying.
This post was edited on 12/16/19 at 1:44 pm
Posted on 12/16/19 at 1:43 pm to WG_Dawg
“River Crossing Riddle” (or whatever the frick it’s titled)
Posted on 12/16/19 at 1:43 pm to Who_Dat_Tiger
I may have been unclear.
Divide the 12 into 4 groups of 3. Have 2 groups sit on the seesaw. If they are equal, discard them.
Your odd man will be in the remainder,
From those remaining 6, pick 4
Then have them sit on the seesaw. If it is equal, discard those and have the remainder sit on the saw.
If they are tilted then take the heavier 2 and have them sit on the saw.
Divide the 12 into 4 groups of 3. Have 2 groups sit on the seesaw. If they are equal, discard them.
Your odd man will be in the remainder,
From those remaining 6, pick 4
Then have them sit on the seesaw. If it is equal, discard those and have the remainder sit on the saw.
If they are tilted then take the heavier 2 and have them sit on the saw.
Posted on 12/16/19 at 1:45 pm to fr33manator
Stop being overly difficult.
Posted on 12/16/19 at 1:45 pm to yankeeundercover
It’s more understandable visually.
Now who can answer my riddle
Now who can answer my riddle
Posted on 12/16/19 at 1:45 pm to yankeeundercover
Eleventy seven
Posted on 12/16/19 at 1:46 pm to fr33manator
That only works if you know the oddball is heavier. I assumed that too. But the riddle does not state that.
This post was edited on 12/16/19 at 1:47 pm
Posted on 12/16/19 at 1:48 pm to mark65mc
quote:
One side will weigh more than the other. That narrows the field by half.
But you don't know if the person of different weight is lighter or heavier so no, no new information is derived from this act of obvious stupidity.
Posted on 12/16/19 at 1:48 pm to LNCHBOX
quote:
Other than eliminating half the field, right?
Which half did you eliminate?
Posted on 12/16/19 at 1:50 pm to noonan
quote:
That only works if you know the oddball is heavier.
quote:fricking duh
But the riddle does not state that.
Posted on 12/16/19 at 1:52 pm to LNCHBOX
quote:
Other than eliminating half the field, right?
It doesn't eliminate half the field
It just verifies what you already know to be true and wastes a turn
frick man
Posted on 12/16/19 at 1:52 pm to Powerman
quote:Ok... so 11 people weigh exactly the same... 1 person doesn’t... it doesn’t matter whether he’s heavier or lighter... the riddle only asked “weighs differently”.
Powerman
Troll on, trolla :ohsnap:
Posted on 12/16/19 at 1:52 pm to Who_Dat_Tiger
quote:
a dime and a nickel. One of them is a nickel
One of them is not a nickel. But the other one is.
Posted on 12/16/19 at 1:52 pm to yankeeundercover
Just have the men get up on there 2 at a time. The law of averages tells us the one that weighs different will be in one of the groups that gets scaled. This way you have no doubt.
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