Any of you follow World of Engineering on Twitter?

The horse was a female doctor

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First one is 288

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I got 101.25

I would say the first one is 45. I don’t know the math behind the second but I would think that the downward force would be greater on the one on the outside of the block.

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First one would be a good time to remember all the sin, cos, tan relationships. It's likely pretty easy math with those. Pythagorean theorem will solve it easy enough though

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First one is 36

i get 45 (44.99...) for a. visually that looks close as if you lay the tilted square flat it would be between 6 and 7 units all (3+2+1+a little due to the tilt)^2

All the triangles formed on the left side share the same angle. Therefore all side are proportional.

Triangle formed by 4 and 9 squares is 3 on one side and 3-2 or 1 on the other side. Therefore the big triangle formed by 1, 4, 9 is 6 on one side and 2 on the other.

6^2 + 2^2 = c^2

36+4=40

40=c2 and since a square is base x height area = 40.

A = 40

The first one is 45.

Used trig to do it

Make a right triangle using the three boxes. That gives you a side length of six (3+2+1).

Now make another triangle on the left side which contains the 2x2 box. The base also has to be six because of laws of congruency (right triangles sharing two identical angles and the connecting side must be congruent).

Now make a smaller triangle using the side of the 2x2 box to find the angle. You have the height (2). Length is simply 6 - 2 (whole length minus length of small box) which is 4.

Now you’ve got two sides of a right triangle. 2 and 4. Inverse tangent gets you the angle.

I’m getting the angle as 26.56505118.

Make another big triangle to calculate length of side x of the big square; you’ve got one side (6) and angle. 6/cosine theta gives you length of side.

That puts the hypotenuse, or side x of square at 6.708 and change

X^2= 45 which is your answer