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Started By
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re: Math Problem: Saw this on FB and now I'm depressed
Posted on 11/18/16 at 10:17 am to lsupride87
Posted on 11/18/16 at 10:17 am to lsupride87
quote:
He is just a douche sometimes. He knows what you are saying is technically right
It isn't though.
1
Posted on 11/18/16 at 10:17 am to theunknownknight
The answer is 15...the cheeseburger represents 5, the bear mug represents 1 and the bear bottle represents 10. Multiplication takes priority so it would be 10x1=10+5=15
Posted on 11/18/16 at 10:17 am to LNCHBOX
quote:
I don't agree to disagree
quote:
LNCHBOX
Checks out.
Posted on 11/18/16 at 10:18 am to slackster
There is only one answer to this problem. I'm not catering to idiots trying to justify their stupidity. That's how you end up with Hillary Clinton.
This post was edited on 11/18/16 at 10:19 am
Posted on 11/18/16 at 10:18 am to NYNolaguy1
quote:Im not sure why he is arguing against this
X1=bottle
X2=burger
X3=image of 1 beer mug
X4=image of 2 beer mugs
The only way you can solve it is by assuming that 2*X3=X4, yet that equation was not given as part of the original three.
Posted on 11/18/16 at 10:18 am to LNCHBOX
quote:
I don't agree to disagree. You are wrong. The mugs are even the exact same size. There is no possible argument you can make to justify your position anymore.
I am not wrong. You are just being extremely obtuse and/or don't understand how higher level math variables work. You continually are just making an assumption on the value of one mug. Whatever man. Keep being your usual dick self.
Posted on 11/18/16 at 10:18 am to theunknownknight
17?
Bottles worth 10
Burgers worth 5
Mugs worth 2
Unless this is a trick.
Bottles worth 10
Burgers worth 5
Mugs worth 2
Unless this is a trick.
Posted on 11/18/16 at 10:19 am to LNCHBOX
quote:Yes, it is
It isn't though.
Posted on 11/18/16 at 10:19 am to BaddestAndvari
quote:
in order to get the correct answer you are performing a logical math problem inside of the physical math problem which is really stupid
It uses inconsistent reasoning as a device to throw in a trick. Kind of silly.
Posted on 11/18/16 at 10:19 am to TigerGrad2011
quote:
they are different pictures.
Nope. There is just a different quantity. They are the exact same picture of the exact same object. You're trying too hard.
Posted on 11/18/16 at 10:19 am to mlminbtr
quote:
he bear mug represents 1
How?
Posted on 11/18/16 at 10:19 am to MaroonWhite
quote:
Let's call the bottles x, the hamburgers y, and the mugs z.
These then are the first 3 equations:
3x = 30
x + 2y = 20
y + 2z = 9
Solve for the value of a bottle (x) using the first equation:
x = 30 / 3
x= 10
Now that x is known, we can solve for the value of a hamburger (y) using the second equation:
10 + 2y = 20
y = 10 / 2
y = 5
Now that X and y are known, we can solve for the value of a mug (z) using the third equation:
5 + 2z = 9
z = 4 / 2
z = 2
So
x = 10
y = 5
z = 2
And solving the fourth equation using operator precedence (parenthesis added for clarity):
5 + (2 * 10) = 25
exactly why I posted what I posted
In order to create what LNCHBOX is saying, you have to make a logic step out of algebra and actually break down z a little more, which is really dumb
10 + 2y = 20
y = 10 /2
y = 5
--
Up to this point the pictures were the pictures, so there was no altering of anything, and it was what it is... but z
It's actually:
5 + 2z = 9
z = 4/2
z = 2 where z = 2 Jugs of Beer
5 + ((2/2) * 10) = 15
It's really bad logic's, but I think this stupid click bait was meant to be that way
Posted on 11/18/16 at 10:20 am to monkeybutt
quote:
You are just being extremely obtuse and/or don't understand how higher level math variables work.
They're nothing high level about this. You're over complicating it.
Posted on 11/18/16 at 10:20 am to OweO
You are missing a multiplication symbol. Also, the trick is that they use 2 mugs when it is first presented and 1 mug in the last equation.
Posted on 11/18/16 at 10:20 am to ell_13
With letters:
A + A + A = 30
A + B + B = 20
B + 2C + 2C = 9
B + C x A = ?
3A = 30
A = 10
10 + 2B = 20
B = 5
5 + 4C = 9
C = 1
So... 5 + 1 x 10 = 15
A + A + A = 30
A + B + B = 20
B + 2C + 2C = 9
B + C x A = ?
3A = 30
A = 10
10 + 2B = 20
B = 5
5 + 4C = 9
C = 1
So... 5 + 1 x 10 = 15
Posted on 11/18/16 at 10:20 am to LNCHBOX
(no message)
This post was edited on 8/14/23 at 11:07 pm
Posted on 11/18/16 at 10:21 am to theunknownknight
It takes more than 3 beers to get me drunk
Posted on 11/18/16 at 10:21 am to ell_13
(no message)
This post was edited on 8/14/23 at 11:07 pm
Posted on 11/18/16 at 10:22 am to BaddestAndvari
Yep, you are right.
Posted on 11/18/16 at 10:22 am to TigerGrad2011
quote:
It's a picture you idiot...they are different pictures. The pictures are variables in the equation. One picture is defined, one picture isn't defined.
You are making an assumption which does not equal mathematical certainty.
Gun to your head and you had to give the correct answer or you die:
A. 60
B. 25
C. 15
D. None of the above.
This post was edited on 11/18/16 at 10:26 am
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