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re: Math Problem: Saw this on FB and now I'm depressed
Posted on 11/18/16 at 10:11 am to theunknownknight
Posted on 11/18/16 at 10:11 am to theunknownknight
It's either 15 or 60
0
Posted on 11/18/16 at 10:11 am to MrSpock
quote:
Is the mug not 1?
There are 4 in the 3rd picture.
The answer can be 15 or 25, depending on if the a-hole who drew it even knew he was picturing a different "amount" with his jugs of beer.
The "real" answer is 15 - but honestly, in order to get the correct answer you are performing a logical math problem inside of the physical math problem which is really stupid
This post was edited on 11/18/16 at 10:12 am
Posted on 11/18/16 at 10:11 am to jimbeam
quote:Umm, I dont either?
Even if a beer mug is 2, I don't need a calculator to solve 5+2x10
Posted on 11/18/16 at 10:12 am to LNCHBOX
quote:
No, I just am not stupid. The answer is 15.
Can I throw a monkey wrench into this problem and simply state that it's unsolvable?
There's 4 unknowns and 3 equations
Posted on 11/18/16 at 10:12 am to monkeybutt
quote:
Or variable "picture of two beer mugs = X", variable "picture of one beer mug = ?" You can assume its 1/2 X, I'm not gonna assume that.
Like I said, Agree to disagree.
I don't agree to disagree. You are wrong. The mugs are even the exact same size. There is no possible argument you can make to justify your position anymore.
Posted on 11/18/16 at 10:12 am to NYNolaguy1
There aren't 4 unknowns.
Posted on 11/18/16 at 10:12 am to BaddestAndvari
quote:This. This should end the thread
The answer can be 15 or 25, depending on if the a-hole who drew it even knew he was picturing a different "amount" with his jugs of beer.
The "real" answer is 15 - but honestly, in order to get the correct answer you are performing a logical math problem inside of the physical math problem which is really stupid
Posted on 11/18/16 at 10:13 am to LNCHBOX
quote:Now you are being 100% wrong. They are cartoon pictures. The cartoon picture of 1 beer mug was never actually defined
I don't agree to disagree. You are wrong. The mugs are even the exact same size. There is no possible argument you can make to justify your position anymore.
This post was edited on 11/18/16 at 10:14 am
Posted on 11/18/16 at 10:13 am to LNCHBOX
(no message)
This post was edited on 8/14/23 at 11:11 pm
Posted on 11/18/16 at 10:14 am to slackster
Let's call the bottles x, the hamburgers y, and the mugs z.
These then are the first 3 equations:
3x = 30
x + 2y = 20
y + 2z = 9
Solve for the value of a bottle (x) using the first equation:
x = 30 / 3
x= 10
Now that x is known, we can solve for the value of a hamburger (y) using the second equation:
10 + 2y = 20
y = 10 / 2
y = 5
Now that X and y are known, we can solve for the value of a mug (z) using the third equation:
5 + 2z = 9
z = 4 / 2
z = 2
So
x = 10
y = 5
z = 2
And solving the fourth equation using operator precedence (parenthesis added for clarity):
5 + (2 * 10) = 25
These then are the first 3 equations:
3x = 30
x + 2y = 20
y + 2z = 9
Solve for the value of a bottle (x) using the first equation:
x = 30 / 3
x= 10
Now that x is known, we can solve for the value of a hamburger (y) using the second equation:
10 + 2y = 20
y = 10 / 2
y = 5
Now that X and y are known, we can solve for the value of a mug (z) using the third equation:
5 + 2z = 9
z = 4 / 2
z = 2
So
x = 10
y = 5
z = 2
And solving the fourth equation using operator precedence (parenthesis added for clarity):
5 + (2 * 10) = 25
Posted on 11/18/16 at 10:14 am to lsupride87
quote:
He is still tech right.
He isn't though. The mugs are the exact same, size color etc. So if two mugs=2, one of the exact same mug=1.
Posted on 11/18/16 at 10:14 am to LNCHBOX
quote:
LNCHBOX
Why you so butthurt bro?
Posted on 11/18/16 at 10:14 am to TigerGrad2011
quote:He is just a douche sometimes. He knows what you are saying is technically right
It doesn't matter if the beer mugs look exactly the same, it's the fact that it is a completely different picture...I know what you are saying, you just can't seem to get what we are saying through that thick skull of yours.
Posted on 11/18/16 at 10:16 am to LNCHBOX
quote:No. Cartoon picture of two mugs was defined=1
He isn't though. The mugs are the exact same, size color etc. So if two mugs=2, one of the exact same mug=1.
That has no real life value to a number so it has to be defined.
So to have 100% certainty, cartoon picture of 1 beer mug has to be defined.
It is logical to assume it is 1. There I agree with you. But it is still ASSUMED
This post was edited on 11/18/16 at 10:16 am
Posted on 11/18/16 at 10:16 am to TigerGrad2011
quote:
It doesn't matter if the beer mugs look exactly the same,
If the mugs being the same doesn't matter, then what's to stop you from saying the bottles have different values in each equation?
Posted on 11/18/16 at 10:16 am to theunknownknight
With letters:
A + A + A = 30
A + B + B = 20
B + 2C + 2C = 9
B + C x A = ?
3A = 30
A = 10
10 + 2B = 20
B = 5
5 + 4C = 9
C = 1
So... 5 + 1 x 10 = 15
A + A + A = 30
A + B + B = 20
B + 2C + 2C = 9
B + C x A = ?
3A = 30
A = 10
10 + 2B = 20
B = 5
5 + 4C = 9
C = 1
So... 5 + 1 x 10 = 15
Posted on 11/18/16 at 10:16 am to LNCHBOX
This thread is still going? How is anyone getting anything but 15?
Oh and nice edit post #2 in thread. One way to make a save.
Oh and nice edit post #2 in thread. One way to make a save.
Posted on 11/18/16 at 10:16 am to lsupride87
quote:
Cartoon picture of two mugs was defined=1
Wrong.
Posted on 11/18/16 at 10:17 am to LNCHBOX
quote:
There aren't 4 unknowns.
X1=bottle
X2=burger
X3=image of 1 beer mug
X4=image of 2 beer mugs
The only way you can solve it is by assuming that 2*X3=X4, yet that equation was not given as part of the original three.
Posted on 11/18/16 at 10:17 am to LNCHBOX
(no message)
This post was edited on 8/14/23 at 11:08 pm
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