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Posted on 12/16/19 at 3:24 pm to yankeeundercover
I've heard a version of this where she does it so she'll see him again at the funeral bc she's a psychopath, but your version says they had a great time and in love so that wouldn't make sense
Posted on 12/16/19 at 3:27 pm to yankeeundercover
quote:
A woman goes to her mother’s funeral and meets a man. They don’t exchange names or contact information, but she and the man hit it off spectacularly and get along perfectly. The event ends happily, and while the woman is completely smitten with the man and seemingly in love, the following week the woman kills her own sister.
She was a twin and the man sleeps with her twin?
Or the man is her sisters husband
Give me a few and I’ll think up some more scenarios.
Posted on 12/16/19 at 3:28 pm to WG_Dawg
Actually disregard my post I read too fast, that's the answer. To see him again
Posted on 12/16/19 at 3:28 pm to OysterPoBoy
quote:well shite, if we can just assume, I will pick him out of the crowd.
I think being trapped on an island we can assume the odd person is heavier.
I have no idea.
If you do it in 4s, you could get to it in four uses, but that is as good as I got.
Posted on 12/16/19 at 3:28 pm to TheArrogantCorndog
quote:
Magma/lava?
Was looking for pyroclastic specifically, but pretty much yes
Posted on 12/16/19 at 3:36 pm to fr33manator
She’s crazy and the guy runs the funeral home. She doesn’t have his contact info so in her warped mind attending another funeral of a relative is her only way to see him.
Posted on 12/16/19 at 3:39 pm to yankeeundercover
2 groups of 6
3 vs 3 on see saw now its down to 6
in abnormal group of 6:
3 from abnormal group vs 3 known normal and 3 not weighed - now down to 3, and you now know if 12th person is fat/skinny
now weigh 2 of the last 3
(not winner, winner)
3 vs 3 on see saw now its down to 6
in abnormal group of 6:
3 from abnormal group vs 3 known normal and 3 not weighed - now down to 3, and you now know if 12th person is fat/skinny
now weigh 2 of the last 3
(not winner, winner)
This post was edited on 12/16/19 at 3:56 pm
Posted on 12/16/19 at 3:40 pm to junior
To all things and men I appertain,
and yet by some am shunned and distained.
Fondle me and ogle me til you’re insane,
but no blow can harm me, cause me pain.
Children delight in me, elders take fright.
Fair maids rejoice and spin.
Cry and I weep, yawn and I sleep.
Smile, and I too shall grin.
What am I?”
and yet by some am shunned and distained.
Fondle me and ogle me til you’re insane,
but no blow can harm me, cause me pain.
Children delight in me, elders take fright.
Fair maids rejoice and spin.
Cry and I weep, yawn and I sleep.
Smile, and I too shall grin.
What am I?”
Posted on 12/16/19 at 3:41 pm to junior
quote:
2 groups of 6
3 vs 3 on see saw now its down to 6
in abnormal group of 6:
3 from abnormal group vs 3 known normal and 3 not weighed - now down to 3, and you now know if 12th person is fat/skinny
now weigh 2 of the last 3
winner, winner
Which one is the abnormal one?
Posted on 12/16/19 at 3:41 pm to BOSCEAUX
quote:
What am I?”
Long winded.
Posted on 12/16/19 at 3:42 pm to junior
What if the two you weigh, weigh differently? Who’s to say which one weighs the same as the others?
Posted on 12/16/19 at 3:47 pm to junior
quote:
3 from abnormal group vs 3 known normal and 3 not weighed - now down to 3, and you now know if 12th person is fat/skinny
Only if the 3 you pick from abnormal group has the fat/skinny person in it. If the see saw doesn’t tilt you are still down to 3 but you don’t know if the outlier is fat or thin. On your 3rd and final try the only way you know for sure is if the see saw doesn’t tilt and thus the guy not on it is the outlier.
Posted on 12/16/19 at 3:48 pm to Displaced
quote:
A reflection.
Winner.
Witcher 3 fan?

Posted on 12/16/19 at 4:00 pm to BOSCEAUX
quote:
Only if the 3 you pick from abnormal group has the fat/skinny person in it.
Any abnormal group should have the heavier guy. The other 11 are the same weight, so if you have the same # on each side, any abnormal result is the heavy guy.
Posted on 12/16/19 at 4:09 pm to Rep520
quote:
Any abnormal group should have the heavier guy. The other 11 are the same weight, so if you have the same # on each side, any abnormal result is the heavy guy.
His abnormal group is 6 individuals with one in the group being the outlier. It would be mere chance that the 3 he picks out of this group to weigh against his known group contains the outlier.
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