re: 9 – 3 ÷ 1/3 + 1 = ?

You are laughing at me getting the correct answer?

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9 – 3 ÷ 1/3 + 1 = ?

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A) That's a very poorly written problem, intended to be confusing. No real engineer or anyone else with a firm grasp of math would write a problem in that manner.

B) As is it written, the answer is 9.

quote:

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That doesn't end the thread though because whatever a-hole.wrote the problem used "÷" and "/" which leads to.confusuikna nd would.neber happen in a real world problem.

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Still not as confusing as the jibberish you just typed.

Anyone saying 9 is doing this:
3 * 1/3 = 1 + 9 - 1 = 9

But the answer is dividing by 1/3
3 / 1/3 = 3 * 3/1 = 9
9 - 9 + 1 = 1

Edit: apparently the 9s are interpreting this as (3 divided by 1) divided by 3. Which means they’re adding some weird parentheses that dont exist. It’s actually more confusing trying to piece together incorrect logic

It depends on if the 1/3 is a fraction or if it is a shorthand for division.

Considering that if it were supposed to be division I would think it would be written as 9-(3÷1)/3+1 I will go with it being a fraction, so...

3÷1/3 = 9
9-9 = 0
0+1 = 1

It's 1 my man...anything besides that is bad engineering and a waste of a degree, i guess

The spaces have nothing to do with it. It's the fact that they used ÷ and /.

If they used two ÷ signs, the answer would be 9. But since they used a ÷ and /, it's clear that you are supposed to be dividing 3 by one-third.

I know I just wanted to quote what you typed before the edit and make fun of your fat thumbs.

9 – 3 ÷ 1/3 + 1
=9 - 3 / 3 + 1
=9 - 1 + 1
= 9

There are no parentheses around the "1/3" which is why it isn't 1

If 1/3 is a fraction, the answer has to be 1.
I hate these poorly written problems.