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re: Math Problem: Saw this on FB and now I'm depressed
Posted on 11/18/16 at 10:47 am to TigerGrad2011
Posted on 11/18/16 at 10:47 am to TigerGrad2011
quote:
First step for you to understand: it does not matter if the mugs are identical or not.
Then none of the other variables matter either. The bottle can be 10 in the first equation and 15 in the next. Why not?
2
Posted on 11/18/16 at 10:47 am to TigerGrad2011
It's like you're trying to say it's logical to assume that 2 mugs together could include a discount; therefore who knows what a single mug would cost?
Posted on 11/18/16 at 10:47 am to LNCHBOX
quote:Yes. And healthcare. So I hope you feel safe the next time you walk into a surgery room in the NOLA area that someone as meticulous as me validated the operational and financial controls of the area.
Audit?
Posted on 11/18/16 at 10:49 am to LNCHBOX
quote:
Then none of the other variables matter either. The bottle can be 10 in the first equation and 15 in the next. Why not?
You are being extremely obtuse here.
Posted on 11/18/16 at 10:49 am to lsupride87
why is this getting personal? 
Posted on 11/18/16 at 10:50 am to TigerGrad2011
Are we sure that the mugs are identical? What if the mug in the back has some weird bulge on the left side that we can't see?
Posted on 11/18/16 at 10:51 am to OneMoreTime
quote:
Are we sure that the mugs are identical? What if the mug in the back has some weird bulge on the left side that we can't see?
Posted on 11/18/16 at 10:51 am to OneMoreTime
Posted on 11/18/16 at 10:51 am to theunknownknight
Whups, edited to 60.
This post was edited on 11/18/16 at 10:53 am
Posted on 11/18/16 at 10:52 am to ell_13
quote:No idea. LNCH is feeling the heat I guess.
why is this getting personal?
This post was edited on 11/18/16 at 10:52 am
Posted on 11/18/16 at 10:52 am to LNCHBOX
This post was edited on 8/14/23 at 10:58 pm
Posted on 11/18/16 at 10:52 am to theunknownknight
Burger is 5
Beer is 10
Mugs(2) is 2...so I'm assuming a single mug is 1
5 + 1 x 10
No parentheses, so 5 + 10 would be 15
Aside from the missing mug, I wonder what other picture I'm overlooking.
Beer is 10
Mugs(2) is 2...so I'm assuming a single mug is 1
5 + 1 x 10
No parentheses, so 5 + 10 would be 15
Aside from the missing mug, I wonder what other picture I'm overlooking.
This post was edited on 11/18/16 at 10:56 am
Posted on 11/18/16 at 10:52 am to OneMoreTime
quote:
Are we sure that the mugs are identical? What if the mug in the back has some weird bulge on the left side that we can't see?
Also, let's not assume that all beer is created equally here. Do both really have the same beer? Is it even beer?
Posted on 11/18/16 at 10:52 am to monkeybutt
quote:
You are being extremely obtuse here.
I'm doing exactly what you're doing.
Posted on 11/18/16 at 10:53 am to TigerGrad2011
quote:
The first three variables are defined through the equations.
The fourth is never defined.
There are only three variables.
Posted on 11/18/16 at 10:53 am to TigerGrad2011
quote:Even after proving, at the very least, that this is the dumber of the two "assumptions", you're still sticking with it, huh?
The first three variables are defined through the equations.
The fourth is never defined.
Bold.
This post was edited on 11/18/16 at 10:57 am
Posted on 11/18/16 at 10:55 am to larry289
quote:
Whups, edited to 60.
Is there something to assume it's (5+1) x 10? and not 5 + 1 x 10
Serious question. I did not notice the missing mug until later.
Posted on 11/18/16 at 10:56 am to ell_13
Can't assume that the mugs are identical, so you can't assume that the bulgeless mug is worth 1/2 of the 2 mugs. Case closed.
Posted on 11/18/16 at 10:56 am to OneMoreTime
Obviously.
Posted on 11/18/16 at 10:57 am to monkeybutt
quote:yeah but it isn't logical.... the pictures of the beer mugs look identical for a reason.
That you can't understand this way of looking at the problem is not my problem
Be practical
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