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can anyone help with these 2 math problems?

Posted on 11/1/15 at 5:27 pm
Posted by skeeter531
Member since Jun 2014
2493 posts
Posted on 11/1/15 at 5:27 pm
find the next number in the sequence.

7, 16, 8, 27, 9

choices:
27
10
40
37

2,7,26,101,400

choices:
1595
800
595
1840

On the first one I was thinking that the relationship between the first, third, and fifth numbers is independent of the relationship between the second, fourth, and missing sixth number. The difference between the second and fourth number is 11 but if you add 11 to 27 you get 38 and that's not an answer.

In the second one, again I think the first, third, and fifth numbers are related (even numbers) and the second, fourth, and sixth are related (odd numbers) leaving choices 1595 and 695. Furthermore I notice in the number 101 there is the same number in the ones and hundreds place, as in the number 1595. But I can't find a connection to the number 7.

Anyone?
Thanks in advance!
Posted by DrSteveBrule
Baton Rouge
Member since Sep 2009
12549 posts
Posted on 11/1/15 at 5:28 pm to
I think problem 1 is 40.

8x2 is 16, 9x3 is 27, 10x4 is 40

I'm going 1595 for problem 2

Divide a number by the preceding number, you'll see it ranged between about 3.5 and 4. 1595 gives you the most similar answer. Otherwise I don't see a relationship.
This post was edited on 11/1/15 at 5:32 pm
Posted by El Segundo Guy
1-866-DHS-2-ICE
Member since Aug 2014
11748 posts
Posted on 11/1/15 at 5:29 pm to
1 is 40
This post was edited on 11/1/15 at 5:31 pm
Posted by TDsngumbo
Member since Oct 2011
51639 posts
Posted on 11/1/15 at 5:29 pm to
I'm not doing your homework for you.

Mostly because I don't know how.
Posted by CherryGarciaMan
Sugar Magnolia
Member since Aug 2012
2497 posts
Posted on 11/1/15 at 5:29 pm to
First answer would be 40.
Next number after that would be 10.

Not sure on second.


Second one is 1595.
101-1 times 4 minus 5.
This post was edited on 11/1/15 at 5:33 pm
Posted by bradwieser
Cornell Fan
Member since May 2008
10555 posts
Posted on 11/1/15 at 5:29 pm to
37
1595
Posted by WG_Dawg
Member since Jun 2004
91115 posts
Posted on 11/1/15 at 5:30 pm to
288
288
Posted by hoopsgalore
Chicago
Member since Nov 2013
9161 posts
Posted on 11/1/15 at 5:31 pm to
12
Posted by demtigers73
Member since Aug 2014
6209 posts
Posted on 11/1/15 at 5:33 pm to
Best Answer: 7, 16, 8, 27, 9, ...
8*2 = 16
9*3 = 27
10*4 = 40
The next number is 40.


The series is obtained by multiplying the previous number by 4 and then subtracting (n - 1).
1st number = 2 - ( 1 - 1) = 2
2nd number = (4 x 2) - (2 - 1) = 7
3rd number = (4 x 7) - (3 - 1) = 26
4th number = (4 x 26) - (4 - 1) = 101
5th number = (4 x 101) - (5 - 1) = 400
6th number = (4 x 400) - (6 - 1) = 1595
Posted by MrSpock
Member since Sep 2015
5166 posts
Posted on 11/1/15 at 5:37 pm to
quote:

2,7,26,101,400


2 x 4 = 8 --> minus 1 for 1st position = 7

7 X 4 = 28 --> minus 2 for 2nd position = 26

26 x 4 = 104 --> minus 3 for 3rd position = 101

101 x 4 = 404 --> minus 4 for 4th position = 400

400 x 4 = 1600 --> minus 5 for 5th position = 1595




Posted by KindaRaw
Member since Jun 2014
3963 posts
Posted on 11/1/15 at 5:37 pm to
quote:

Best Answer: 7, 16, 8, 27, 9, ...
8*2 = 16
9*3 = 27
10*4 = 40
The next number is 40.


The series is obtained by multiplying the previous number by 4 and then subtracting (n - 1).
1st number = 2 - ( 1 - 1) = 2
2nd number = (4 x 2) - (2 - 1) = 7
3rd number = (4 x 7) - (3 - 1) = 26
4th number = (4 x 26) - (4 - 1) = 101
5th number = (4 x 101) - (5 - 1) = 400
6th number = (4 x 400) - (6 - 1) = 1595

Would you please show us the common core method of this problem? TIA
Posted by TROLA
BATON ROUGE
Member since Apr 2004
14985 posts
Posted on 11/1/15 at 5:39 pm to
No.1 my mind tells me 37 but 40 also makes since

1595 is the second one with the sequencing using the number 4 as the multiplier
Posted by skeeter531
Member since Jun 2014
2493 posts
Posted on 11/1/15 at 5:48 pm to
thanks for the help! (and it's not my homework lol!)
Posted by Tshiz
Idaho
Member since Jul 2013
7974 posts
Posted on 11/1/15 at 5:56 pm to
First one is 40.

Time two plus two. Then divide by two. Times three plus three, then divide by three. Next is times 4 plus 4. Then divide by 4. And so on.

Second one I didn't read bc youre dumb
This post was edited on 11/1/15 at 5:57 pm
Posted by skeeter531
Member since Jun 2014
2493 posts
Posted on 11/1/15 at 5:57 pm to
quote:

First one is 40. Time two plus two. Then divide by two. Times three plus three, then divide by three. Next is times 4 plus 4. Then divide by 4. And so on. Second one I didn't read bc your dumb


I know how to spell "you're". asswipe.
Posted by skeeter531
Member since Jun 2014
2493 posts
Posted on 11/1/15 at 5:58 pm to
ha...you edited. But you still spelled it wrong. It has an apostrophe.
Posted by retired trucker
midwest
Member since Feb 2015
5093 posts
Posted on 11/1/15 at 6:11 pm to
I'd mark 1. 40
Posted by Sao
East Texas Piney Woods
Member since Jun 2009
68469 posts
Posted on 11/1/15 at 6:13 pm to

23. It all leads back to 23.
Posted by reginaphilange
Member since Mar 2014
415 posts
Posted on 11/1/15 at 6:27 pm to
You are correct. The relationship for the second problem is you multiply the number by 4 then subtract 1, by 4 then subtract 2, by 4 then subtract 3....and so on.
Posted by mikrit54
Robeline
Member since Oct 2013
8664 posts
Posted on 11/1/15 at 6:41 pm to
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