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re: Could your wife or girlfriend solve this?
Posted on 2/14/25 at 10:28 am to anc
Posted on 2/14/25 at 10:28 am to anc
The problem with the tweeter's hypothesis is it isn't a test of intelligence UNLESS the person has been previously taught Euclidean geometry. If this is the case then it can be a mark of intelligence if they can see the relationships and see how to use the Pythagorean theorem to solve for the length of one side of the square.
Education does not equal intelligence.
Education does not equal intelligence.
1
Posted on 2/14/25 at 10:28 am to anc
Pi is 3.14
Posted on 2/14/25 at 10:30 am to anc
Posted on 2/14/25 at 10:30 am to anc
x=10, area of the square = 100sq units?
Posted on 2/14/25 at 10:30 am to BlackAdam
quote:
Nobody can solve that without making assumptions.
No assumptions needed. I don't agree with the Tweeters premise on Valentine's Day, I just thought it was interesting.
This post was edited on 2/14/25 at 10:32 am
Posted on 2/14/25 at 10:30 am to Mingo Was His NameO
quote:
A(x)^2+B(y)^2=C^2 A(5)^2+B(20)^2=C^2 X and Y have to be equal. There’s enough information
Right. But in this scenario, x and y can equal any number.
Theeefore the answer can be any number.
Posted on 2/14/25 at 10:31 am to anc
48x2 should be easy for most adults to do without a calculator.
This problem here is a completely unnecessary skill to have. No one is going to ask you to find the area of a square inside of a triangle for any reason in your life.
48x2 is literally used on a daily bases.
This is nowhere near the same thing, and I agree everyone should know how to perform that in their head.
This problem here is a completely unnecessary skill to have. No one is going to ask you to find the area of a square inside of a triangle for any reason in your life.
48x2 is literally used on a daily bases.
This is nowhere near the same thing, and I agree everyone should know how to perform that in their head.
Posted on 2/14/25 at 10:31 am to SantaFe
quote:
Someone got 100, would like to see their work.
Which is incorrect.
Posted on 2/14/25 at 10:31 am to anc
Wife, yes.
GF, no way.
GF, no way.
Posted on 2/14/25 at 10:32 am to poochie
quote:
Right. But in this scenario, x and y can equal any number. Theeefore the answer can be any number.
This can’t be serious
Posted on 2/14/25 at 10:33 am to anc
I used a business card to measure the 20, the 5, and the box on my screen. The box's sides are closer to 7. It's not half of 20 or double 5. Suck it
This post was edited on 2/14/25 at 10:34 am
Posted on 2/14/25 at 10:38 am to anc
triangles are proportional as they share the same angles. therefore, the length of the sides are proportional
the square 10x10=100 sq in
the square 10x10=100 sq in
Posted on 2/14/25 at 10:39 am to anc
It's solvable because the same angles in the smaller triangle are equal to the same angles in the larger triangle.
It's been years since I've mathed that hard.
Something along the lines of cos of 5 = sin of 20
Then use that to find the unknown side length.
The green area is a square, so all sides are equal length.
ETA: I was somewhat correct. This guy from India explains it all
It's been years since I've mathed that hard.
Something along the lines of cos of 5 = sin of 20
Then use that to find the unknown side length.
The green area is a square, so all sides are equal length.
ETA: I was somewhat correct. This guy from India explains it all
This post was edited on 2/14/25 at 12:41 pm
Posted on 2/14/25 at 10:41 am to anc
The boy’s mother is a doctor.
Posted on 2/14/25 at 10:41 am to anc
They do not provide enough info to solve it. We do not know the interior angles outside of the 90 degree angle, additionally the lengths of the sides is not given.
Posted on 2/14/25 at 10:42 am to Shexter
The previous 4 years the angles were part of a trans-triangle and they could be whatever they wanted.
It's all different now.
It's all different now.
Posted on 2/14/25 at 10:42 am to anc
For fun, there's a way to do it without trig functions at all. You know the area of the whole shape and the area of the parts have to be equal. You can set up equations, set them equal to each other, and solve for x.
Posted on 2/14/25 at 10:43 am to anc
quote:
You and I are in a race. I am in second place and you pass me. What place are you in?
Still in first place because I just lapped you bud.
Posted on 2/14/25 at 10:43 am to Ingeniero
quote:
For fun, there's a way to do it without trig functions at all. You know the area of the whole shape and the area of the parts have to be equal. You can set up equations, set them equal to each other, and solve for x.
That's awesome. I learned something.
Posted on 2/14/25 at 10:44 am to BRUNNIN4
lol people who ask these little questions are always dweebs
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