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Started By
Message
re: Mathematicians Are So Close to Cracking This 82-Year-Old Riddle
Posted on 8/8/20 at 8:05 pm to Bestbank Tiger
Posted on 8/8/20 at 8:05 pm to Bestbank Tiger
quote:
Any power of 2 takes you back to 2^0.
If n is odd 3n + 1 is even.
And all the riddle is saying is that eventually 3n + 1 will be a power of 2.
0
Posted on 8/8/20 at 8:23 pm to hikingfan
Posted on 8/8/20 at 8:24 pm to hikingfan
I still have trouble with 9th grade algebra. frick this shite.
Posted on 8/9/20 at 7:53 am to hikingfan
The answer is 350
Posted on 8/9/20 at 8:05 am to Brosef Stalin
quote:
That looks a Calc 1 problem. Not too hard to solve.
That looks nothing like calculus. Also, it’s easy to solve for a given number, but that is not the problem. The problem is to PROVE that it either does, or does not, resolve to 1 for the infinity of real numbers. Try it, Gomer.
Posted on 8/9/20 at 8:09 am to Rouge
quote:
Infinity / 2 is still infinity.
Therefore, you can never get back down to one.
“Infinity” is not a natural number.
Posted on 8/9/20 at 8:24 am to hikingfan
Yea, I was done with math as soon as letters got involved. Sorry, but 2+2 does not equal x.
Posted on 8/9/20 at 8:29 am to onelochevy
No but I have been told 2+2=5 these days
Posted on 8/9/20 at 8:42 am to hikingfan
Who cares
Posted on 8/9/20 at 8:42 am to hikingfan
quote:
Take any natural number. There is a rule, or function, which we apply to that number, to get the next number. We then apply that rule over and over, and see where it takes us. The rule is this: If the number is even, then divide it by 2, and if the number is odd, then multiply by 3 and add 1.
quote:
It’s definitely true for all numbers with less than 19 digits
quote:
Tao’s results says that any counterexamples to the Collatz Conjecture are going to be incredibly rare. There’s a deep meaning to how rare we’re talking here, but it’s still very different from nonexistent.
Posted on 8/9/20 at 9:46 am to hikingfan
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