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re: How does the Fibonacci sequence get past 0?
Posted on 1/3/25 at 5:38 am to TackySweater
Posted on 1/3/25 at 5:38 am to TackySweater
0
Posted on 1/3/25 at 6:05 am to TackySweater
Fibonacci was born in 1170 in Pisa and three years later they broke ground for the leaning tower of Pisa. It took hundreds of years to construct, so thankfully he never had to see it lean, which probably would have been unbearable for him.
Posted on 1/3/25 at 6:20 am to TackySweater
There are 618 reasons why
Posted on 1/3/25 at 7:33 am to Synoptic
quote:
Synoptic
quote:Name checks out
Serious answer is that its initial input is defined as the pair 0, 1. If the initial default was only 0, and not the pair 0,1, then it would not get past zero. In fact, there would be no sequence at all (not even zeroes). The sequence needs to start with an input number pair for X1 and X2 because X3 and greater is defined as Xn = Xn-1 + Xn-2. So if only X1 is given as an input and not X1 and X2, then Xn where n is greater than 1 is not defined. A number in a sequence not existing is not the same as the number in a sequence being zero.
Posted on 1/3/25 at 7:50 am to Klark Kent
quote:
one of my favorite Ted Talks is on the Fibonacci sequence. i use it regularly with relative sizing.
It’s a favorite in our household as well. It’s become an annual tradition for us to get together and watch it every Columbus Day.
Posted on 1/3/25 at 8:16 am to TackySweater
quote:
How does the Fibonacci sequence get past 0?
0 isnt a number, nothing to get past
Posted on 1/3/25 at 9:32 am to TackySweater
How is the "G" in "lonGevity" pronounced twice?
Posted on 1/3/25 at 6:08 pm to LordSaintly
It’s most often given starting with 0, 1
LINK
Some sources start it with 1,1. You can start a sequence the same rule (Xn = Xn-1 + Xn-2 for n greater than 2) with any pair of integers, and as long as they are not both zero the sequence will have many of the same properties as the original Fibonacci sequence.
LINK
Some sources start it with 1,1. You can start a sequence the same rule (Xn = Xn-1 + Xn-2 for n greater than 2) with any pair of integers, and as long as they are not both zero the sequence will have many of the same properties as the original Fibonacci sequence.
This post was edited on 1/3/25 at 7:19 pm
Posted on 1/3/25 at 6:10 pm to Synoptic
quote:
Serious answer is that its initial input is defined as the pair 0, 1. If the initial default was only 0, and not the pair 0,1, then it would not get past zero. In fact, there would be no sequence at all (not even zeroes). The sequence needs to start with an input number pair for X1 and X2 because X3 and greater is defined as Xn = Xn-1 + Xn-2. So if only X1 is given as an input and not X1 and X2, then Xn where n is greater than 1 is not defined. A number in a sequence not existing is not the same as the number in a sequence being zero.
This is what I've been trying to tell everybody but they won't listen.
Posted on 1/3/25 at 6:32 pm to TackySweater
quote:
How does the Fibonacci sequence get past 0?
It's because there is no such thing as zero (unless, of course you are talking about dollars in my wallet).
Posted on 1/3/25 at 6:50 pm to Btrtigerfan
quote:
Btrtigerfan
I fricking knew someone was going to post Lateralus.
Posted on 1/3/25 at 6:57 pm to Spankum
quote:
but Chat GPT
I'm drinking tonight
Posted on 1/3/25 at 7:02 pm to LordSaintly
quote:
Because it doesn’t start with 0
Oh ok
Posted on 1/3/25 at 7:04 pm to IT_Dawg
quote:
0 isnt a number, nothing to get past
Uhhh
Posted on 1/3/25 at 7:04 pm to Grievous Angel
quote:
How is the "G" in "lonGevity" pronounced twice?
It’s not
Posted on 1/3/25 at 7:06 pm to Klark Kent
Ted Talks are that short? I thought they were much longer than 6 minutes.
Posted on 1/3/25 at 7:10 pm to TackySweater
good question. i’ll see if i can’t find the full thing
Posted on 1/3/25 at 7:17 pm to Klark Kent
quote:
good question. i’ll see if i can’t find the full thing
Is this the part you were referencing or one longer?
Posted on 1/3/25 at 8:29 pm to TackySweater
Zero doesn't exist. Go ask Young Sheldon.
Posted on 1/3/25 at 8:36 pm to TackySweater
When you touch yourself
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