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re: 2nd grade math homework - what is the correct answer?
Posted on 2/4/18 at 8:46 am to Will Cover
Posted on 2/4/18 at 8:46 am to Will Cover
49-36=13
13/2=6.5
36+6.5=42.5
It’s a stupid question.
13/2=6.5
36+6.5=42.5
It’s a stupid question.
0
Posted on 2/4/18 at 8:47 am to Cowboyfan89
quote:
or the moron who wrote this question
I think it is clear the intention was for the kids to subtract 36 from 49. It was just completely mis-worded.
As a teacher, I have seen this stuff quite a bit. The taxpayers pay an assload of money to someone to come up with a “scope and sequence” ( which anyone can view at labelieves.com).
When I actually try to start teaching from this thing it is clear that it was half assed vetted. Some of the answers on the answer keys are essentially made up because I can’t even find them in the readings. The reading level of sixth graders wasn’t even considered and if I went by it faithfully and with fidelity the kids would be bored out of there minds.
This post was edited on 2/4/18 at 8:48 am
Posted on 2/4/18 at 8:48 am to Will Cover
quote:
2nd grade math homework
quote:
Large dogs are “x”
x + (x + 36) = 49
2x + 36 = 49
2x = 13
x = 6.5
x + 36 = 42.5 (small dogs)
Congrats on the Asian kid
Posted on 2/4/18 at 9:00 am to Will Cover
...36...
Posted on 2/4/18 at 9:02 am to Will Cover
Not that I went to a top public school system, but that question seems a bit advanced for second graders.
Regardless if it is incorrectly worded.
Regardless if it is incorrectly worded.
Posted on 2/4/18 at 9:19 am to flvelo12
Answer = Op lies.
Posted on 2/4/18 at 9:32 am to Will Cover
Putting aside the fact that I also got 42.5 as an answer, how in the world does anyone think the answer is 36? I get how people don't read the question well enough and then quickly correct themselves but some people actually stick with that answer? Unbelievable.
Posted on 2/4/18 at 9:45 am to Will Cover
quote:
Nice edit after Googling.
You didn’t stipulate that I couldn’t google.
Posted on 2/4/18 at 9:47 am to Will Cover
42.5
Posted on 2/4/18 at 9:53 am to lnomm34
quote:
Poor half dogs.
Assume the dog show is in a Korean market and there is no requirement for live dogs.
Posted on 2/4/18 at 10:03 am to Will Cover
X = Large dogs
X + 36 = Small dogs
Large + Small = 49
X + X + 36 = 49
2X = 13
X = 6.5
Stupidly written question.
X + 36 = Small dogs
Large + Small = 49
X + X + 36 = 49
2X = 13
X = 6.5
Stupidly written question.
This post was edited on 2/4/18 at 10:04 am
Posted on 2/4/18 at 10:08 am to Will Cover
I don’t believe this is second grade math. This is 8th grade minimum, maybe 7th grade honors class.
Second graders still eat their boogers and shite in their pants.
Second graders still eat their boogers and shite in their pants.
Posted on 2/4/18 at 1:40 pm to deeprig9
42.5 is mathematically correct but a nonsensical answer. Which defeats the entire purpose of a word problem - with a word problem you're supposed to use critical thought to help you arrive at the answer, and everyone knows there's no such thing as a half-dog.
If the word problem doesn't hold up to logic, ditch it and just have a strict algebra problem.
If the word problem doesn't hold up to logic, ditch it and just have a strict algebra problem.
Posted on 2/4/18 at 2:51 pm to lnomm34
quote:You got the correct answer but Inthink you have some error in your equation going from "knowns" to "unknowns". Using x then it magically disappears?
X + Y = 49
Let Y = small dogs
Let X = large dogs
Y+ 36 = X
(Y + 36) + Y = 49
2Y + 36 = 49
2Y = 13
Y = 6.5
If "x" equals large dogs then it can't represent total dogs.
Posted on 2/4/18 at 3:34 pm to Geauxtiga
(no message)
This post was edited on 2/13/25 at 6:18 am
Posted on 2/4/18 at 3:50 pm to Bestbank Tiger
quote:
42.5 is mathematically correct but a nonsensical answer. Which defeats the entire purpose of a word problem - with a word problem you're supposed to use critical thought to help you arrive at the answer, and everyone knows there's no such thing as a half-dog.
If the word problem doesn't hold up to logic, ditch it and just have a strict algebra problem.
Maybe it's an essay question. "To start, it's fair to assume there are only small and large dogs, but this assumption leads to fractional dogs, which is absurd. Thus, there must be more types than small/large, which creates the possibility there are no large dogs, so here is the range of possible small dog counts, 36 to 42." That would take a pretty bright 2nd grader indeed.
Posted on 2/4/18 at 4:18 pm to Spock's Eyebrow
Easy math...
100/2=50
50-10=40
40/7=5.7
5.7+36.8=42.5
Duh
100/2=50
50-10=40
40/7=5.7
5.7+36.8=42.5
Duh
Posted on 2/4/18 at 4:50 pm to Will Cover
You can't do it. if there are 36 more small dogs than big dogs, the number of small dogs plus the number of big dogs must equal an even number. Since the final total number of dogs they're looking for is an odd number, you can't do it. Not without a saw, at least.
There. I've answered it using only logic and no algebra and the OT still will have no idea what's going on because you are some stupid motherfrickers.
There. I've answered it using only logic and no algebra and the OT still will have no idea what's going on because you are some stupid motherfrickers.
This post was edited on 2/4/18 at 4:54 pm
Posted on 2/4/18 at 5:03 pm to Will Cover
36. No math involved.
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