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Started By
Message
1
Posted on 5/14/14 at 1:06 pm to DosManos
quote:
How the hell is the radius 13cm?
You have to relate the given numbers to get a right triangle with a base of 5cm and the adjacent has to be 1cm shorter than the hypotenuse.
5:12:13 triangle
This post was edited on 5/14/14 at 1:07 pm
Posted on 5/14/14 at 1:08 pm to junkfunky
Why does the hypotenuse of the 5:12:13 triangle equal the radius of that circle?
Posted on 5/14/14 at 1:09 pm to Seven Costanza
quote:
Was he just looking to see if you would clarify the question?
It was just a start up question, he sat down introduced himself and then right off the bat he asked me this question. This was followed by a million questions on power related things.
quote:
How did you get 13 cm?
you need to use pythagorean theorem.
Posted on 5/14/14 at 1:09 pm to Seven Costanza
quote:
Posted by Seven Costanza Why does the hypotenuse of the 5:12:13 triangle equal the radius of that circle?
It's the only line in the triangle that goes from the center to a point on the completed circle.
Posted on 5/14/14 at 1:10 pm to junkfunky
It must be shittily drawn to scale because I don't see how the adjacent could extend for another 11 cm.
ETA: shite, ignore me
ETA: shite, ignore me
This post was edited on 5/14/14 at 1:12 pm
Posted on 5/14/14 at 1:11 pm to DosManos
quote:
How the hell is the radius 13cm?
I use an online calculator for work that I have bookmarked, but this is the actual formula.
Posted on 5/14/14 at 1:13 pm to dj30
quote:
you need to use pythagorean theorem.
WRONG
I just used solid edge.
Posted on 5/14/14 at 1:14 pm to ashy larry
What job were you interviewing for?
Posted on 5/14/14 at 1:15 pm to ashy larry
Ok that formula makes sense, but I don't think OP used that during the interview.
I understand that the hypotenuse is the only one reaching from the center to the outside point, but how do I know that the lower corner of the triangle (the starting point of the hypotenuse) is starting in the center?
ETA: Thank you, junkfunky
I understand that the hypotenuse is the only one reaching from the center to the outside point, but how do I know that the lower corner of the triangle (the starting point of the hypotenuse) is starting in the center?
ETA: Thank you, junkfunky
This post was edited on 5/14/14 at 1:19 pm
Posted on 5/14/14 at 1:16 pm to Seven Costanza
Kinda hard to explain but this is how I worked it.
Posted on 5/14/14 at 1:16 pm to TigerHam85
quote:
WRONG
I just used solid edge.
Well, didnt really have access to that at an interview. Just pencil and paper.
Posted on 5/14/14 at 1:17 pm to DosManos
quote:
ETA: shite, ignore me
DosManos, what was your revelation? I should be getting this, but something is going over my head.
ETA: Thank you, junkfunky
This post was edited on 5/14/14 at 1:19 pm
Posted on 5/14/14 at 1:17 pm to doublecutter
quote:
What job were you interviewing for?
It was an electrical engineering position.
Posted on 5/14/14 at 1:17 pm to dj30
that shite drawing is not to scale.... I can't handle that
Posted on 5/14/14 at 1:18 pm to junkfunky
OOOOOOOOOOOOOOOOOOOOOOOOOOOOOO
Thank you, junkfunky! Now I won't have to lose sleep tonight.
Thank you, junkfunky! Now I won't have to lose sleep tonight.
Posted on 5/14/14 at 1:21 pm to Seven Costanza
Posted on 5/14/14 at 1:22 pm to junkfunky
this
Posted on 5/14/14 at 1:23 pm to dj30
took me way too long, but:
a^2 + b^2 = c^2
(r-1)^2 + 5^2 = r^2
r^2 - 2r + 1 + 25 = r^2
r = 13
a^2 + b^2 = c^2
(r-1)^2 + 5^2 = r^2
r^2 - 2r + 1 + 25 = r^2
r = 13
Posted on 5/14/14 at 1:25 pm to ashy larry
Interesting, never used the formula before.
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