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re: Settle This Facebook Math Problem

Posted on 9/20/17 at 1:02 am to
Posted by Psychoanalysis
Shreveport
Member since Aug 2017
125 posts
Posted on 9/20/17 at 1:02 am to
Are you choosing to ignore my questions on purpose or are you not able to understand them?


quote:

You can't buy and sell anything in $10 increments and gain a $20 profit.


I agree assuming the increments are even. But they aren't. He has three positives and only 1 negative. You continally say that the 10 between horses is a net negative, but it isn't, it's a net wash. You are forgetting one side of the equation.

Assuming it's a loan:

First horse transaction +10
"buy" Loan +10
Second horse transaction +10
"sell" Repayment - 10
20 profit
This post was edited on 9/20/17 at 1:04 am
Posted by djmicrobe
Planet Earth
Member since Jan 2007
4970 posts
Posted on 9/20/17 at 1:02 am to
60 Out Of Pocket
70-60=10 Profit
60+10+10Profit=80
OOP=70
90-70=20Profit
10Profit+20Profit=30Profit
Posted by pioneerbasketball
Team Bunchie
Member since Oct 2005
139098 posts
Posted on 9/20/17 at 1:02 am to
you made $11.
Posted by pioneerbasketball
Team Bunchie
Member since Oct 2005
139098 posts
Posted on 9/20/17 at 1:03 am to
I disagree.
Posted by Korkstand
Member since Nov 2003
29134 posts
Posted on 9/20/17 at 1:04 am to
quote:

I have a Dollar. I buy a toy.

I sell toy for $11. I made $10.

I buy toy for $10, I sell for $21. Are you saying I did not make $20??
No, you made $21 (assuming you spent your entire dollar buying the first toy).

$1 + $10 = $11 total spent
$11 + $21 = $32 total income

$32-$11=$21 profit.
Posted by Napoleon
Kenna
Member since Dec 2007
74900 posts
Posted on 9/20/17 at 1:05 am to
I made $11 on a TRANSACTION. The single transaction I made $11.

I start with $1 I end with $21. I made $20. I made $20. I made $20.

I could then sell the item for $31, make another $10 ON THE TRANSACTION and I would have made $30, because I star...............


Man, you are trolling, I took the bait.

Posted by Psychoanalysis
Shreveport
Member since Aug 2017
125 posts
Posted on 9/20/17 at 1:05 am to
Show me where I'm wrong? Specifically?

Lay out your exact problem like I did.

Use an equation to show me I'm wrong.

In the alternative show me where this is wrong:
Beginning balance (line value:0)[net problem value:0]
-
First horse purchase (60)[-60]
+
First horse sale (70)[+10]
+
Loan (10)[+20]
-
Second horse purchase (80)[-60]
+
Second horse sale (90)[+30]
-
Repayment of loan (10)[+20]
=
20
This post was edited on 9/20/17 at 1:09 am
Posted by Napoleon
Kenna
Member since Dec 2007
74900 posts
Posted on 9/20/17 at 1:07 am to
You can disagree with History, or Science, you can never disagree with math.

Let me make it simple.

Johnny has spent $70 on a horse, he sells it to Mary for $90. How much did Johnny make?

Because in this scenario the seller has out of pocket expenses totaling $70 and income totalling $90.

Posted by Korkstand
Member since Nov 2003
29134 posts
Posted on 9/20/17 at 1:07 am to
quote:

Show me where I'm wrong?
You're wrong for continually arguing (like several of us have), while pioneer is trolling.
Posted by Napoleon
Kenna
Member since Dec 2007
74900 posts
Posted on 9/20/17 at 1:07 am to
He cast a line with a lure and we all bit.

Posted by pioneerbasketball
Team Bunchie
Member since Oct 2005
139098 posts
Posted on 9/20/17 at 1:10 am to
Plot twist: He was selling the horse to himself and made no profit.?
Posted by Psychoanalysis
Shreveport
Member since Aug 2017
125 posts
Posted on 9/20/17 at 1:10 am to
(no message)
This post was edited on 9/20/17 at 1:40 am
Posted by pioneerbasketball
Team Bunchie
Member since Oct 2005
139098 posts
Posted on 9/20/17 at 1:11 am to
PEMDAS Brah
Posted by Psychoanalysis
Shreveport
Member since Aug 2017
125 posts
Posted on 9/20/17 at 1:14 am to
Thank you for admitting I was right
This post was edited on 9/20/17 at 1:40 am
Posted by Korkstand
Member since Nov 2003
29134 posts
Posted on 9/20/17 at 1:14 am to
quote:

Plot twist: He was selling the horse to himself and made no profit.?
Posted by pioneerbasketball
Team Bunchie
Member since Oct 2005
139098 posts
Posted on 9/20/17 at 1:15 am to
He buys for 60 but sells for 70: +10
He sold for 70 but then buys back for 80: -10
He bought for 80 but then sells for 90: +10

If you add those up you get only a profit of $10.

Or a more natural way the thought process might happen "He bought for 60 and sold for 70 so he is up 10. But oh no, he bought it back for 80, that's a $10 loss so he's back to 0 profit. He sold it again for 90, that's $10 profit on his 80 buy so he's 10 up again!"

Thinking of transactions in pairs like this is how you get profits from reselling an item or rebuying something you sold. So it's a very intuitive and automatic way to think of these transactions. Of course what they've ended up doing is double counting the 2 middle transaction, treating it as 6 transactions when really it's 4.?
Posted by Napoleon
Kenna
Member since Dec 2007
74900 posts
Posted on 9/20/17 at 1:20 am to
simply put. He spent $70 out of pocket and ended with $90.

He made $20.

Posted by Psychoanalysis
Shreveport
Member since Aug 2017
125 posts
Posted on 9/20/17 at 1:21 am to
quote:

But oh no, he bought it back for 80, that's a $10 loss


It's not. You can't buy something for 80 using 70. It is a 10 loss, but he had to add 10 in in order to get to 80.

That's the problem with your equation and your line of thinking. It doesn't matter if it's the same horse or a different horse, you can't buy something for 80 using 70. You have to add an additional 10 in there which cancels out the perceived loss.

Forget the entire problem and answer me this question:

Imagine his atm card transactions for that day:

Starting balance:0
Withdraw $60
Deposit $70
Withdraw $80
Deposit $90

Ending balance=20

That's a net gain of $20. His bank account has risen by $20. How can you say that although his account has risen by $20 he only made $10?
This post was edited on 9/20/17 at 1:29 am
Posted by Spock's Eyebrow
Member since May 2012
12300 posts
Posted on 9/20/17 at 1:22 am to
quote:

He buys for 60 but sells for 70: +10
He sold for 70 but then buys back for 80: -10
He bought for 80 but then sells for 90: +10

If you add those up you get only a profit of $10.

Or a more natural way the thought process might happen "He bought for 60 and sold for 70 so he is up 10. But oh no, he bought it back for 80, that's a $10 loss so he's back to 0 profit. He sold it again for 90, that's $10 profit on his 80 buy so he's 10 up again!"


Now do as I said earlier ferchrissakes and look at the cash flows:

Format: (cash flow, running total)

1: -60, -60
2: 70, 10
3: -80, -70
4: 90, 20

20 is what you end up with. FFS.
Posted by pioneerbasketball
Team Bunchie
Member since Oct 2005
139098 posts
Posted on 9/20/17 at 1:23 am to
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