re: Settle This Facebook Math Problem

If he only started with $60 available, the answer is $10 because he would need to borrow another $10 to afford the $80 for the final $10 on the last sale, thus negating the last sale completely

Only has $60 to start:

Buys horse for $60
Sells for $70
$10 profit

Borrows $10
Now has $80

Buys horse for $80
Sells for $90

Now has $20 profit, but owes $10
Ends with $10


But none of that matters since the original problem doesn't expressly say the buyer has exactly $60 to start, so the answer is $20

quote:

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If he only started with $60 available, the answer is $10 because he would need to borrow another $10 to afford the $80 for the final $10 on the last sale, thus negating the last sale completely

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Ok, I got it now. That's what I was doing.

He bought the horse for $60
sold for $70
buys back for $80

He had to have $70 to start with.

Horse sells for $90 so he makes twenty bucks.

Correct answer is break even.

It's $20 total profit all day long

$10 on first transaction
$10 on second transaction

We are arguing the same point... I was showing the math on the only possible outcome of $10 profit... which is he couldn't afford the $10 jump, thus causing him to borrow $10, thus negating the final transaction

Damn some of you are stupid. The correct and final answer us $20. What is so difficult.

End this thread before we become more stupider. Lol

quote:

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The answer is $10

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I've got a cat for sale at $70... Wanna play this out in person??

quote:

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It's $20 total profit all day long

$10 on first transaction
$10 on second transaction

We are arguing the same point... I was showing the math on the only possible outcome of $10 profit... which is he couldn't afford the $10 jump, thus causing him to borrow $10, thus negating the final transaction

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But you're saying there's a way he could get to $10 profit. There is not. He would still profit $20 even having to repay a $10 loan.

quote:

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The answer is $10

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I can see that some of you are hooked on the complexity of the problem and some don't understand how a loan works on a ledger.

In simple terms:

Started with 60.
Ended with 90.
30 net increase

Borrowed 10
So 30-10=

$20 net profit.

It has been explained multiple times in this thread.

In the absolute simplest terms:

0-60+70+10-80+90-10=20

If you are still confused:


Beginning balance (line value:0)[net problem value:0]
-
First horse purchase (60)[-60]
+
First horse sale (70)[+10]
+
Loan (10)[+20]
-
Second horse purchase (80)[-60]
+
Second horse sale (90)[+30]
-
Repayment of loan (10)[+20]
=
20

To continue to insist otherwise is an exercise in futility and a blatant show of ignorance.

Please feel free to copy and paste this for anyone who doesn't understand:


He borrows 60 to buy the horse, then sells it for 70, he pays back the 60 and now has $10 in his pocket.

He then borrows 70, adds it to the 10 in his pocket and buys the horse for 80, then sells it for 90. He pays back the 70 loan and is left with 20 in his pocket.

Of course its $20 profit, unless he only has $60 at his disposal, which the problem does not expressly state... thus the only explanation for him finishing with $10 profit is to start with exactly $60, otherwise he makes $20

$10 black
+
$10 red
+
$10 black
=
$10 black