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Odds of guessing a card back to back?
Posted on 8/11/17 at 9:10 pm
Posted on 8/11/17 at 9:10 pm
InB4 Three Fiddy
I was shuffling cards one day and asked someone to guess a card I picked. They picked it (10 hearts). I put it back into the deck, shuffle and pull another card. They pick it again (Ace clubs).
Question is what are the odds of this happening? Is it 1:52 because the picks are independent of each other or is it 1:104, or ever greater?
I was shuffling cards one day and asked someone to guess a card I picked. They picked it (10 hearts). I put it back into the deck, shuffle and pull another card. They pick it again (Ace clubs).
Question is what are the odds of this happening? Is it 1:52 because the picks are independent of each other or is it 1:104, or ever greater?
13
Posted on 8/11/17 at 9:10 pm to theantiquetiger
I am going with greater.
Posted on 8/11/17 at 9:11 pm to theantiquetiger
Time for you to buy a lotto ticket
Posted on 8/11/17 at 9:11 pm to theantiquetiger
Fiddy/Fiddy
U is either right or u is wrong
U is either right or u is wrong
Posted on 8/11/17 at 9:12 pm to theantiquetiger
No to both.
You suck at math.
You suck at math.
Posted on 8/11/17 at 9:12 pm to theantiquetiger
quote:
Is it 1:52 because the picks are independent of each other or is it 1:104, or ever greater?
Neither.
It's a frickton more than that.
Posted on 8/11/17 at 9:13 pm to theantiquetiger
1:2704 to be exact
Posted on 8/11/17 at 9:13 pm to theantiquetiger
(1/52)*(1/52)
So about .037%
So about .037%
This post was edited on 8/11/17 at 9:16 pm
Posted on 8/11/17 at 9:16 pm to theantiquetiger
(1/52)*(1/52) --> 1/2704
This post was edited on 8/11/17 at 9:17 pm
Posted on 8/11/17 at 9:17 pm to Jcorye1
I still believe it is only 1:52 because the picks are independent of each other.
This post was edited on 8/11/17 at 9:20 pm
Posted on 8/11/17 at 9:17 pm to theantiquetiger
Some people's lucky guesses wins million dollar lotteries. You just wasted yours on picking useless cards
Posted on 8/11/17 at 9:17 pm to theantiquetiger
(1/52) * (1/52) = you're answer
Posted on 8/11/17 at 9:19 pm to theantiquetiger
Then you are still wrong.
Posted on 8/11/17 at 9:20 pm to BigPerm30
quote:
1:2704 to be exact
You got the correct answer in 3 minutes. OT doing work tonight.
Posted on 8/11/17 at 9:22 pm to theantiquetiger
They are independent. When events are independent you multiply the probabilities. (1/52)*(1/52)
Posted on 8/11/17 at 9:22 pm to theantiquetiger
quote:
I still believe it is only 1:52 because the picks are independent of each other.
No. You're not using that concept correctly in this scenario.
You're talking about the odds of picking the correct card twice in two attempts.
Posted on 8/11/17 at 9:24 pm to theantiquetiger
We should play a game of no limit hold em some time 
Posted on 8/11/17 at 9:24 pm to white perch
On a roulette table, there are 38 numbers (with 0 & 00).
The odds of rolling a 10 is 1:38. The odds of a 10 being rolled on next spin is still 1:38 because the spins are independent of each other.
The odds of rolling a 10 is 1:38. The odds of a 10 being rolled on next spin is still 1:38 because the spins are independent of each other.
Posted on 8/11/17 at 9:26 pm to white perch
If the second guess was truly an add on to the first, for example card one was guessed then removed as a possibility for guess two, then the odds would be 1/52 * 1/51 or 1/2652. The way you described it is card one was guessed, put back into play, then card two was guess. That would be what others had said 1/2704.
This post was edited on 8/11/17 at 9:28 pm
Posted on 8/11/17 at 9:27 pm to UGATiger26
quote:
You're talking about the odds of picking the correct card twice in two attempts.
That's what happened. I didn't ask them to guess what two cards I am about to take out of the deck, I asked him to guess a card I just picked. When he got it correct, I bet him he couldn't do it again, and he did.
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