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Math Riddle: How much string would you add....
Posted on 7/25/14 at 6:05 pm
Posted on 7/25/14 at 6:05 pm
Let's say the earth was perfectly round and smooth, and you ran a string all the way around the equator - 25,000 miles. And then your wife comes along and wants the string to sit exactly 1 foot off the ground - all the way around.
Question: how much new string do you add to the original string to make that happen?
Here's the cryptic answer (shhhhh! don't reveal it!): LINK
Question: how much new string do you add to the original string to make that happen?
Here's the cryptic answer (shhhhh! don't reveal it!): LINK
This post was edited on 7/25/14 at 6:11 pm
16
Posted on 7/25/14 at 6:06 pm to tigerpawl
Do you even circumference, bro?
Posted on 7/25/14 at 6:07 pm to tigerpawl
wut
Posted on 7/25/14 at 6:07 pm to tigerpawl
Can't I just put all of it in a big container and put the container one foot off the ground.
Posted on 7/25/14 at 6:08 pm to tigerpawl
I'd tell her to get her arse back in the kitchen and make me dinner.
Posted on 7/25/14 at 6:08 pm to tigerpawl
I'm not married. Next question.
Posted on 7/25/14 at 6:09 pm to tigerpawl
Is this actually a riddle?
Posted on 7/25/14 at 6:12 pm to tigerpawl
C= 25000 = 2*PI*R ==> R=25000/(2*PI)
C' = 2*PI*(25000/(2*PI)+1)
Calculate the radius, add 1, recalculate Circumference. Subtract C'-C
Oops. Correction as noted: Convert 1' increment to 1/5280 miles.
C' = 2*PI*(25000/(2*PI)+1)
Calculate the radius, add 1, recalculate Circumference. Subtract C'-C
Oops. Correction as noted: Convert 1' increment to 1/5280 miles.
This post was edited on 7/25/14 at 6:22 pm
Posted on 7/25/14 at 6:14 pm to tigerpawl
The surprising thing is that the answer is independent of the size of the sphere.
Posted on 7/25/14 at 6:15 pm to Spock's Eyebrow
quote:Ahhhh.... I see you've been there and done that. Works for basketballs too....
The surprising thing is that the answer is independent of the size of the sphere.
Posted on 7/25/14 at 6:16 pm to tigerpawl
Approximately 25,004' ?
Posted on 7/25/14 at 6:17 pm to RDOtiger
quote:refer to the OP link for the "cryptic answer"... How much new string would you add to the original 25,000 mile string?
Approximately 25,004' ?
This post was edited on 7/25/14 at 6:18 pm
Posted on 7/25/14 at 6:18 pm to Karnac
quote:
C= 25000 = 2*PI*R ==> R=25000/(2*PI)
C' = 2*PI*(25000/(2*PI)+1)
Calculate the radius, add 1, recalculate Circumference. Subtract C'-C
Forgot to change your units.
Posted on 7/25/14 at 6:19 pm to Karnac
quote:
C= 25000 = 2*PI*R ==> R=25000/(2*PI)
C' = 2*PI*(25000/(2*PI)+1)
Calculate the radius, add 1, recalculate Circumference. Subtract C'-C
You should do some major conversions there or that wont make sense.
Posted on 7/25/14 at 6:19 pm to tigerpawl
quote:
Ahhhh.... I see you've been there and done that. Works for basketballs too....
It's really quite unintuitive.
Posted on 7/25/14 at 6:20 pm to Karnac
Miles and feet homie. Change your units
Posted on 7/25/14 at 6:20 pm to tigerpawl
6.28 feet
Posted on 7/25/14 at 6:21 pm to Karnac
quote:
C= 25000 = 2*PI*R ==> R=25000/(2*PI)
C' = 2*PI*(25000/(2*PI)+1)
Calculate the radius, add 1, recalculate Circumference. Subtract C'-C
You lose points for plugging in a numerical diameter and talking about radii.
ETA: And I lose points for mixing up diameter and circumference.
This post was edited on 7/25/14 at 6:33 pm
Posted on 7/25/14 at 6:21 pm to Chicken
quote:Chicken FTW!! Who started the rumor that Chickens have small brains?
6.28 feet
This post was edited on 7/25/14 at 6:24 pm
Posted on 7/25/14 at 6:22 pm to tigerpawl
Also known as 2Pi
or TWO PIES
or TWO PIES
This post was edited on 7/25/14 at 6:23 pm
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