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re: Ignorant automotive question
Posted on 12/22/15 at 6:35 pm to yankeeundercover
Posted on 12/22/15 at 6:35 pm to yankeeundercover
And to take things even further along your automotive learning walk, the cylinder size only includes the distance between the top of the Pistons and the top of the cylinder where the head meets the block.. Piston all the way down in its stroke.
Cylinder size can be increased by putting g in a crankshaft with a longer stroke making the piston travel further down in the cylinder increasing volume. Also boring the cylinder out to increase its size.
This post was edited on 12/22/15 at 6:36 pm
Posted on 12/22/15 at 6:41 pm to meauxjeaux2
I'm a MPG expert."
Hypermiler?
Hypermiler?
Posted on 12/22/15 at 6:48 pm to yankeeundercover
5.0 is the liters. Cubic inches is 302. A lot depends on heads, intake, cam, exhaust, etc.
Posted on 12/22/15 at 7:32 pm to Weaver
The absolute worst I saw when it comes to this was a t shirt in the 90s. It said something about horses, and 454 of them. Some stupid redneck kid with a shackled up old mustang who had no idea that the number of cubic inches doesn't equal the horsepower.
Posted on 12/22/15 at 7:34 pm to meauxjeaux2
"That thing better be an anvil, or I'll break it."

Posted on 12/29/15 at 1:49 pm to yankeeundercover
quote:
So the "cylinder" is rated/measured at "5.7L"... Does that mean they're pumping in 5.7 liters per "splosion"?
if you turned the crank until the piston was at bottom dead center, filled the cylinder with water, then turned the crank to top dead center, the amount of water displaced by the piston emptying the cylinder would 5.7 liter divided by the number of cylinders. (5.7/8 = .7125 liters per cylinder for an 8 cylinder engine).
the engine inhales 5.7 liters of air/gas mixture for every cycle. it inhales it, compresses it, then 'splodes it. the majority of the contents of the mixture is air, with only a tiny amount of fuel.
so, a motor that turns 2500 rpm at 50 mph and gets 20 mpg inhales 1250 times per minute and burns 2.5 (320 ounces) gallons per hour, or .256 ounces per "splosion. divide that by 8 cylinders, and you get .032 ounces used per 'splosion per cylinder.
since one ounce equals .0295735 liters, each 'splosion in a .7125 liter cylinder uses .000946352 liters of fuel and .711553648 liters of air.
this explanation was meant to be demonstrative, not gospel. if anyone finds any fault with my logic or my math, and would like to discuss it, please do so behind my back so as not to trigger me.
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