- My Forums
- Tiger Rant
- LSU Recruiting
- SEC Rant
- Saints Talk
- Pelicans Talk
- More Sports Board
- Fantasy Sports
- Golf Board
- Soccer Board
- O-T Lounge
- Tech Board
- Home/Garden Board
- Outdoor Board
- Health/Fitness Board
- Movie/TV Board
- Book Board
- Music Board
- Political Talk
- Money Talk
- Fark Board
- Gaming Board
- Travel Board
- Food/Drink Board
- Ticket Exchange
- TD Help Board
Customize My Forums- View All Forums
- Show Left Links
- Topic Sort Options
- Trending Topics
- Recent Topics
- Active Topics
Started By
Message

I need a goof "FAIL" picture
Posted on 9/2/09 at 4:01 pm
Posted on 9/2/09 at 4:01 pm
I have an extra credit assignment for my Statistics class. I need a good "FAIL" picture.
When asked, "given fifty random people in a room, what are the odds that two of them share a birthday?" It is ver easy to give the quick response, 50/365 or 13.7%. This would result in eating a big bowl of
<INSERT "FAIL PICTURE HERE>
The correct way to calculate the odds is to take the odds of two people NOT sharing a birthday, and subtract that from 1.
# of declinng odds of NOT Therefore, 1 minus
pppl factor sharing a odds of NOT sharing
gives--> birthday = odds of sharing
1 364 0.997260274 0.27%
2 363 0.991795834 0.82%
3 362 0.983644088 1.64%
4 361 0.972864426 2.71%
5 360 0.959537516 4.05%
6 359 0.943764297 5.62%
.
.
.
46 319 0.045225597 95.48%
47 318 0.039402027 96.06%
48 317 0.034220391 96.58%
49 316 0.02962642 97.04%
50 315 0.025568007 97.44%
So, with 50 random people in a room, the chances of two of them sharing a birthday are over 97%.
When asked, "given fifty random people in a room, what are the odds that two of them share a birthday?" It is ver easy to give the quick response, 50/365 or 13.7%. This would result in eating a big bowl of
<INSERT "FAIL PICTURE HERE>
The correct way to calculate the odds is to take the odds of two people NOT sharing a birthday, and subtract that from 1.
# of declinng odds of NOT Therefore, 1 minus
pppl factor sharing a odds of NOT sharing
gives--> birthday = odds of sharing
1 364 0.997260274 0.27%
2 363 0.991795834 0.82%
3 362 0.983644088 1.64%
4 361 0.972864426 2.71%
5 360 0.959537516 4.05%
6 359 0.943764297 5.62%
.
.
.
46 319 0.045225597 95.48%
47 318 0.039402027 96.06%
48 317 0.034220391 96.58%
49 316 0.02962642 97.04%
50 315 0.025568007 97.44%
So, with 50 random people in a room, the chances of two of them sharing a birthday are over 97%.
Posted on 9/2/09 at 4:26 pm to bigpapamac
quote:
This would result in eating a big bowl of
Failies
This post was edited on 9/2/09 at 4:27 pm
Posted on 9/2/09 at 4:49 pm to Ajo Devil
quote:
1 364 0.997260274 0.27%
Am I reading this right, and you are saying that with 1 person in a room, there is a .27% chance that 2 people in the room share a birthday?
Posted on 9/2/09 at 4:56 pm to GRTiger
Yes you are, and thanks for the edit. 
Posted on 9/2/09 at 5:38 pm to Ajo Devil
Disregard.
This post was edited on 9/2/09 at 5:39 pm
Posted on 9/2/09 at 7:17 pm to CNB
quote:
Disregard.
ETA:
FWIW - All my self-created FAIL pics are sports related...
Etc...
This post was edited on 9/2/09 at 7:23 pm
Popular
Back to top
2








