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re: Funtime - Solve this simple math problem
Posted on 4/17/21 at 4:18 pm to DomincDecoco
Posted on 4/17/21 at 4:18 pm to DomincDecoco
WTF is this shite? I'm not counting chips in a cookie. If you present me a cookie as a thing of value within an equation, I'm counting the cookie as a thing, not the chips within them.
30/3 Cookies = 10 as the established value of a cookie, frick your chips.
14-(c=10)= 4/2 pair of banana = 2. We've established the value of a single banana is 1.
2+2+10 =14
8-(the value of 2 bananas)= 6/2 clocks =3
2+3+3= 8
3+1+1x10=14
![](https://images.tigerdroppings.com/Images/Icons/IconLOL.gif)
30/3 Cookies = 10 as the established value of a cookie, frick your chips.
14-(c=10)= 4/2 pair of banana = 2. We've established the value of a single banana is 1.
2+2+10 =14
8-(the value of 2 bananas)= 6/2 clocks =3
2+3+3= 8
3+1+1x10=14
![](https://images.tigerdroppings.com/Images/Icons/IconLOL.gif)
Posted on 4/17/21 at 4:20 pm to Lsuhoohoo
It’s 2 + 1 + 1 x 7 = 2 + 1 + 7 = 10
Posted on 4/17/21 at 9:31 pm to Lsuhoohoo
quote:
14-(c=10)= 4/2 pair of banana = 2. We've established the value of a single banana is 1.
Have we? Is 1 worth half of 11? Surely one 1 would be worth half of a pair of 1s. We don’t know if the bananas are placeholders in the tens digits or not.
What if each banana is worth sqrt(2)? Two square roots of 2 adjacent to each other would certainly evaluate to 2.
This post was edited on 4/17/21 at 9:43 pm
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