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re: Math Riddle: How much string would you add....
Posted on 7/25/14 at 7:05 pm to tigerpawl
Posted on 7/25/14 at 7:05 pm to tigerpawl
Surprisingly simple:
The circumference of a circle = 2pi * r (radius)
Therefore, adding 1 foot to the circumference means this is now 2pi * (r+1) = (2pi*r) + 2pi
The extra amount of string required is therefore 2pi times the additional height, in this case 2pi feet.
The circumference of a circle = 2pi * r (radius)
Therefore, adding 1 foot to the circumference means this is now 2pi * (r+1) = (2pi*r) + 2pi
The extra amount of string required is therefore 2pi times the additional height, in this case 2pi feet.
3
Posted on 7/25/14 at 7:15 pm to foshizzle
quote:And for you Alabama fans...
The extra amount of string required is therefore 2pi times the additional height, in this case 2pi feet.
This post was edited on 7/25/14 at 7:17 pm
Posted on 7/25/14 at 8:28 pm to foshizzle
quote:
foshizzle
quote:That's how I figured it out. Sub "circumference" with "radius" #physicsbrain
Therefore, adding 1 foot to the circumference means this is now 2pi * (r+1) = (2pi*r) + 2pi
This post was edited on 7/25/14 at 8:29 pm
Posted on 7/26/14 at 7:58 am to foshizzle
quote:
Therefore, adding 1 foot to the circumference means this is now 2pi * (r+1) = (2pi*r) + 2pi
The extra amount of string required is therefore 2pi times the additional height, in this case 2pi feet.
How do you derive 2pi * (x). where x is the additional height from (2pi*r) + 2pi?
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