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re: Kyle Busch wreck at Daytona was 90 Gs at impact
Posted on 4/16/15 at 12:53 pm to TigerFred
Posted on 4/16/15 at 12:53 pm to TigerFred
Final velocity = 0
initial velocity = 90 miles per hour = 40.2336 meters per second
distance = ?
-(40.2336^2)/(2 x distance) = 882.5985 meters per second
882.5985/9.80665=90 G's
(Meters per second/ Meters per second per G)
Someone better at math figure out the distance Nascar is using to claim the 90 G's...
initial velocity = 90 miles per hour = 40.2336 meters per second
distance = ?
-(40.2336^2)/(2 x distance) = 882.5985 meters per second
882.5985/9.80665=90 G's
(Meters per second/ Meters per second per G)
Someone better at math figure out the distance Nascar is using to claim the 90 G's...
1
Posted on 4/16/15 at 2:28 pm to goldenbadger08
1 G would be accelerating from 9.8 m/s to 0 m/s in 1 second.
90 mph = 40.23 m/s
90xg = (40.23 m/s)/(t)
g = 9.8 m/s
t = 0.0456 s
That means he would have hit the wall and accelerated from 90 mph to 0 mph in 0.045 seconds.
Seems a little high of a number but I haven't seen the wreck.
90 mph = 40.23 m/s
90xg = (40.23 m/s)/(t)
g = 9.8 m/s
t = 0.0456 s
That means he would have hit the wall and accelerated from 90 mph to 0 mph in 0.045 seconds.
Seems a little high of a number but I haven't seen the wreck.
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