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re: Marilyn vos Savant and the history of the Montel Hall question

Posted on 2/23/15 at 4:08 pm to
Posted by link
Member since Feb 2009
19867 posts
Posted on 2/23/15 at 4:08 pm to
what about this

-make the initial pick
-host removes 1/3 of the choices
-then they mix up and randomize the remaining 2 choices. what are the odds you pick the car or goat?
Posted by ell_13
Member since Apr 2013
85311 posts
Posted on 2/23/15 at 4:09 pm to
50/50 at that point.

Everyone is making the flaw of focusing on what you pick where, logically, it makes more sense if you focus on what you don't pick.
This post was edited on 2/23/15 at 4:12 pm
Posted by buckeye_vol
Member since Jul 2014
35255 posts
Posted on 2/23/15 at 4:15 pm to
quote:

what about this

-make the initial pick
-host removes 1/3 of the choices
-then they mix up and randomize the remaining 2 choices. what are the odds you pick the car or goat?
Again this is a completely different game. I would say that your odds are 1/3 in this scenario because the car will remain 2/3 of the time. Since it has been randomized after that, and assuming the car is there you have 1/2 chance of winning. 1/2*2/3= 1/3

The point of the problem is that the car never changes doors. Knowing that, the door you initially choose will never have more than a 1/3 chance.
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