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re: Chemistry question for the OT
Posted on 12/7/15 at 10:29 pm to Bmath
Posted on 12/7/15 at 10:29 pm to Bmath
quote:
No need for the ad hominem attack
Your laughing at my correct answer made me salty...couldn't help myself.
Anyway, you're diluting with pure water with a density of 1.0 g/mL to get to water with a density of 1.025 g/mL.
So,
C1 = 1.03 g/mL
V1 = 315 gal
C2 = 1.00 g/mL
V2 = ?
C3 = 1.025 g/mL
V3 = V1 + V2
C1V1 + C2V2 = C3V3
Since we're actually talking about density, not concentration, the dilution water has a non-zero mass that must be taken into account.
2
Posted on 12/7/15 at 10:49 pm to FutureMikeVIII
quote:
Your laughing at my correct answer made me salty...couldn't help myself.
Fair enough
quote:
Anyway, you're diluting with pure water with a density of 1.0 g/mL
Right, which is what I always assume with making dilutions in the lab. Perhaps what I'm not looking at is I generally am looking to dilute based on percentage. Density is a form of concentration, but it has specific units. Therefore, I could see how the other equation would be more correct. However, it seems odd to me that it would take a full order of magnitude difference in water to make a 0.005 g/mL change.
Posted on 12/7/15 at 11:34 pm to FutureMikeVIII
quote:
C1 = 1.03 g/mL
V1 = 315 gal
C2 = 1.00 g/mL
V2 = ?
C3 = 1.025 g/mL
V3 = V1 + V2
C1V1 + C2V2 = C3V3
Since we're actually talking about density, not concentration, the dilution water has a non-zero mass that must be taken into account.
The chemist in me agrees with all of this. The units of mL and gallons are bothering me even though there wouldn't be a difference in the calculation
ETA: Where's the update??
This post was edited on 12/7/15 at 11:35 pm
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