- My Forums
- Tiger Rant
- LSU Recruiting
- SEC Rant
- Saints Talk
- Pelicans Talk
- More Sports Board
- Fantasy Sports
- Golf Board
- Soccer Board
- O-T Lounge
- Tech Board
- Home/Garden Board
- Outdoor Board
- Health/Fitness Board
- Movie/TV Board
- Book Board
- Music Board
- Political Talk
- Money Talk
- Fark Board
- Gaming Board
- Travel Board
- Food/Drink Board
- Ticket Exchange
- TD Help Board
Customize My Forums- View All Forums
- Show Left Links
- Topic Sort Options
- Trending Topics
- Recent Topics
- Active Topics
Started By
Message
re: Chemistry question for the OT
Posted on 12/7/15 at 9:54 pm to Bmath
Posted on 12/7/15 at 9:54 pm to Bmath
Let x be the amount of water you need to add.
[315/(315+x)]*(1.03)+[x/(315+x)]*(1.00)=1.025
Multiply both sides by (315+x)
315*1.03+x*1.00=1.025(315+x)
324.45+x=322.875+1.025x
.025x=1.575
x=63 gallons
[315/(315+x)]*(1.03)+[x/(315+x)]*(1.00)=1.025
Multiply both sides by (315+x)
315*1.03+x*1.00=1.025(315+x)
324.45+x=322.875+1.025x
.025x=1.575
x=63 gallons
Popular
Back to top
Follow TigerDroppings for LSU Football News