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re: Marilyn vos Savant and the history of the Montel Hall question

Posted on 2/23/15 at 4:54 pm to
Posted by Sid in Lakeshore
Member since Oct 2008
41956 posts
Posted on 2/23/15 at 4:54 pm to
quote:

I have to disagree with the "always switch" conclusion. The correct answer about the probability is that it is 50/50.


Not treading all this but the real answer is:

Door A (your initial selection) = 1/3 chance of winn

Doors B & C (initially not selected) = 2/3 chance of winning.

Show host eliminates Door C (knowing it does not have the car), therefore door B now has the full 2/3 chance of winning.

Door A has 33.3% chance.
Door B has 66.7% chance.

If the car was randomly assigned after the elimination of Door C, the chances would revert to 50/50, but it doesn't happen that way.
Posted by Monk
Baton Rouge
Member since Aug 2007
3660 posts
Posted on 2/23/15 at 4:57 pm to
Solid simple explanation Sid.
Posted by KosmoCramer
Member since Dec 2007
77094 posts
Posted on 2/23/15 at 4:58 pm to
quote:

If the car was randomly assigned after the elimination of Door C, the chances would revert to 50/50, but it doesn't happen that way.


Or if Monty doesn't know and sometimes opens the door with the car, then it is 50/50 as well.

In Let's Make A Deal, you aren't better off switching at the end because all results are independent of each other.
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