re: Marilyn vos Savant and the history of the Montel Hall question

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Take any two doors, where you know that there is a car behind one and a goat behind the other. Pick one. Switch or don't switch, I don't care. Record your results over 100 tries. (Hint: if you flip a coin this will be the same, and easier).

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Well this is irrelevant to the scenario. If this was the game, then why didn't Monty Hall just present two doors?

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The point is: If you accept carrying the initial 3-door probabilities forward, the mathematical proofs are correct. But that is a lie; the problem has been changed to eliminate one non-car door.

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But the probability doesn't change to 50/50 just because there are two choices. It's 66/33.

Here is my question to you. If you were to play the game 100 times, and decided to switch, how many times would you win?