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re: Math Riddle: How much string would you add....

Posted on 7/25/14 at 6:12 pm to
Posted by Karnac
Colorado
Member since Aug 2010
278 posts
Posted on 7/25/14 at 6:12 pm to
C= 25000 = 2*PI*R ==> R=25000/(2*PI)

C' = 2*PI*(25000/(2*PI)+1)

Calculate the radius, add 1, recalculate Circumference. Subtract C'-C

Oops. Correction as noted: Convert 1' increment to 1/5280 miles.
This post was edited on 7/25/14 at 6:22 pm
Posted by lsufan251875
Member since Jul 2008
3159 posts
Posted on 7/25/14 at 6:18 pm to
quote:

C= 25000 = 2*PI*R ==> R=25000/(2*PI)

C' = 2*PI*(25000/(2*PI)+1)

Calculate the radius, add 1, recalculate Circumference. Subtract C'-C



Forgot to change your units.
Posted by SundayFunday
Member since Sep 2011
9322 posts
Posted on 7/25/14 at 6:19 pm to
quote:

C= 25000 = 2*PI*R ==> R=25000/(2*PI)

C' = 2*PI*(25000/(2*PI)+1)

Calculate the radius, add 1, recalculate Circumference. Subtract C'-C




You should do some major conversions there or that wont make sense.
Posted by iAmBatman
The Batcave
Member since Mar 2011
12382 posts
Posted on 7/25/14 at 6:20 pm to
Miles and feet homie. Change your units
Posted by Spock's Eyebrow
Member since May 2012
12300 posts
Posted on 7/25/14 at 6:21 pm to
quote:

C= 25000 = 2*PI*R ==> R=25000/(2*PI)

C' = 2*PI*(25000/(2*PI)+1)

Calculate the radius, add 1, recalculate Circumference. Subtract C'-C


You lose points for plugging in a numerical diameter and talking about radii.

ETA: And I lose points for mixing up diameter and circumference.
This post was edited on 7/25/14 at 6:33 pm
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