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re: Can someone PLEASE help my with this college algebra question please?
Posted on 5/2/14 at 11:32 pm to ReauxlTide222
Posted on 5/2/14 at 11:32 pm to ReauxlTide222
(x(41-0.2x))-21x=460.80
(41x-0.2x^2) – 21x = 460.80
-0.2x^2 + 20x – 460.80 = 0
0.2x^2 - 20x + 460.80 = 0
Quadratic equation
(20+/- (sqrt((-20^2)-(4*0.2*460.80)))) / (2*0.2)
(20+/- (sqrt(400-368.64))) / (0.4)
(20+/- (sqrt(31.36))) / (0.4)
(20+/-5.6)) / (0.4)
(25.6)) / (0.4) or 14.4/0.4
64 or 36
(41x-0.2x^2) – 21x = 460.80
-0.2x^2 + 20x – 460.80 = 0
0.2x^2 - 20x + 460.80 = 0
Quadratic equation
(20+/- (sqrt((-20^2)-(4*0.2*460.80)))) / (2*0.2)
(20+/- (sqrt(400-368.64))) / (0.4)
(20+/- (sqrt(31.36))) / (0.4)
(20+/-5.6)) / (0.4)
(25.6)) / (0.4) or 14.4/0.4
64 or 36
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