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re: Time to discuss the Monty Hall problem (strategy and game show)

Posted on 4/8/14 at 8:04 pm to
Posted by KosmoCramer
Member since Dec 2007
76633 posts
Posted on 4/8/14 at 8:04 pm to
quote:

If the host doesn't know, it could knock your odds down to 0%. Because he could eliminate the door with a car.


You wouldn't make the pick in that scenario, the door would be opened and you lose.
Posted by HurricaneDunc
Houston
Member since Nov 2008
10472 posts
Posted on 4/8/14 at 8:06 pm to
Not a lot of Mensa members in this thread
Posted by genro
Member since Nov 2011
61788 posts
Posted on 4/8/14 at 8:07 pm to
That's what I was saying.
Posted by TH03
Mogadishu
Member since Dec 2008
171114 posts
Posted on 4/8/14 at 8:08 pm to
quote:

You wouldn't make the pick in that scenario, the door would be opened and you lose.


hence the 0% odds

you quoted his post, rephrased it, and acted like he was wrong
Posted by KosmoCramer
Member since Dec 2007
76633 posts
Posted on 4/8/14 at 8:10 pm to
There would be no odds because you wouldn't make the pick. That was my point.

Posted by TH03
Mogadishu
Member since Dec 2008
171114 posts
Posted on 4/8/14 at 8:11 pm to
0% odds, no odds, blah

semantics
Posted by Huey Lewis
BR
Member since Oct 2013
4674 posts
Posted on 4/8/14 at 8:14 pm to
quote:

the host knows. stop creating a new problem to fit what you think is right


Okay, but what if there are 4 doors, 2 doors have cars, and 2 doors have goats. You have to pick 2doors. If you pick 2 goats you win the goats, if you pick 2 cars you win two cars. If you pick one of each you lose.

You pick 2 doors, then the host (who knows what's behind each door) elimates one door at random and opens one of your doors, revealing a goat. Should you open your remaining door, or should you switch to the final door if you're trying to win the goats?
Posted by TH03
Mogadishu
Member since Dec 2008
171114 posts
Posted on 4/8/14 at 8:16 pm to
that's a new problem
Posted by genro
Member since Nov 2011
61788 posts
Posted on 4/8/14 at 8:16 pm to
The surgeon is the boy's mother.
Posted by TH03
Mogadishu
Member since Dec 2008
171114 posts
Posted on 4/8/14 at 8:16 pm to
that student's name?

Albert Einstein
Posted by KosmoCramer
Member since Dec 2007
76633 posts
Posted on 4/8/14 at 8:19 pm to
quote:

You pick 2 doors, then the host (who knows what's behind each door) elimates one door at random and opens one of your doors, revealing a goat. Should you open your remaining door, or should you switch to the final door if you're trying to win the goats?



You apply the same rules. You have a 50/50 chance in the first scenario. Since he removed one, you should switch the pick to increase your odds.

In this scenario I think you have a 75% chance of winning if you switch but there are things I'm not thinking about.
Posted by FootballNostradamus
Member since Nov 2009
20509 posts
Posted on 4/8/14 at 8:32 pm to
quote:

what about this

-make the initial pick
-host removes 1/3 of the choices
-then they mix up and randomize the remaining 2 choices.

what are the odds you pick the car or goat?


This is a different scenario. Since the door removed is ALWAYS a goat, you absolutely have a 2/3 chance of winning if you switch. That is what makes the links dependent.

Read Genro's explanation:

quote:

If you pick a goat, switch and win.

If you pick a car, switch and lose.

What are the odds that you picked a goat? 2/3

That's where it is. Thats all that matters. The number of doors is more or less extraneous.
This post was edited on 4/8/14 at 8:34 pm
Posted by livewire
Member since Aug 2008
999 posts
Posted on 4/8/14 at 8:47 pm to
Regardless of how far out you want to extrapolate it (1000 doors, etc.), if you NEVER change your pick, Monte will always eliminate everything EXCEPT 1 car and one goat, leaving you with a 50/50 shot.
Likewise, if you change your pick EVERY time Monte exposes a new goat, he's still going to leave you with a 50/50 shot in the end.
Extrapolation theory dead!!!
Posted by TH03
Mogadishu
Member since Dec 2008
171114 posts
Posted on 4/8/14 at 8:51 pm to
I'm sure you're right and the mathematical geniuses who have spent time working this problem are wrong
Posted by livewire
Member since Aug 2008
999 posts
Posted on 4/8/14 at 8:53 pm to
Thanks man, that means a lot to me.
Posted by LSUTigerguy789
Los Angeles
Member since Dec 2007
4897 posts
Posted on 4/8/14 at 9:00 pm to
quote:

The point is: If you accept carrying the initial 3-door probabilities forward, the mathematical proofs are correct. But that is a lie;
Why is it a lie?

Link?

Nice troll. Got me.
This post was edited on 4/8/14 at 9:08 pm
Posted by FootballNostradamus
Member since Nov 2009
20509 posts
Posted on 4/8/14 at 9:02 pm to
quote:

Regardless of how far out you want to extrapolate it (1000 doors, etc.), if you NEVER change your pick, Monte will always eliminate everything EXCEPT 1 car and one goat, leaving you with a 50/50 shot. Likewise, if you change your pick EVERY time Monte exposes a new goat, he's still going to leave you with a 50/50 shot in the end. Extrapolation theory dead!!!


Lol you're an idiot.
Posted by gaetti15
AK
Member since Apr 2013
13371 posts
Posted on 4/8/14 at 9:05 pm to
This is why I hate Bayesian statistics
Posted by KosmoCramer
Member since Dec 2007
76633 posts
Posted on 4/8/14 at 9:05 pm to
He's trolling. Hopefully this whole thread is a troll for humanities' sake.
Posted by livewire
Member since Aug 2008
999 posts
Posted on 4/8/14 at 9:07 pm to
quote:

Read Genro's explanation:


quote:

That's where it is. Thats all that matters. The number of doors is more or less extraneous.


Sooooooo Genro says it, it's gold.

I say it, I'm an idiot.
Got it.
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