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re: Math Riddle: How much string would you add....
Posted on 7/25/14 at 8:45 pm to Pectus
Posted on 7/25/14 at 8:45 pm to Pectus
quote:It's a distribution. The 2pi added at the end is the difference and gives you the answer to the problem.
Why add the 2 pi at then end?
foshizzle, mine too. I never got a grad degree. Went straight into teaching high school math, then IT for a power generation company.
This post was edited on 7/25/14 at 8:49 pm
1
Posted on 7/25/14 at 9:30 pm to ell_13
The original string (circumference; 25,000 x 5,280 ft) = 132,000,000 ft
The original diameter = 42,016,904.97626037 ft
The new diameter = 42,016,906.97626037 ft (2 ft longer)
The new circumference = 132,000,006.28318532 ft
Therefore, ergo and hither to...
132,000,006.28318532 ft - 132,000,000 ft = 6.28318532 ft
Diameter/Circumference Calculator
The original diameter = 42,016,904.97626037 ft
The new diameter = 42,016,906.97626037 ft (2 ft longer)
The new circumference = 132,000,006.28318532 ft
Therefore, ergo and hither to...
132,000,006.28318532 ft - 132,000,000 ft = 6.28318532 ft
Diameter/Circumference Calculator
This post was edited on 7/25/14 at 9:41 pm
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