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re: Can someone PLEASE help my with this college algebra question please?
Posted on 5/2/14 at 10:28 pm to ReauxlTide222
Posted on 5/2/14 at 10:28 pm to ReauxlTide222
I sure wont. If you had called me when you and Kelsi got cupcakes at the store RIGHT NEXT TO MY HOUSE maybe I would have but now I refuse!
Sorry, I had to look at all of her FB photos.
I know I have never met her and never will but goddamn she is hot! WELL DONE! You need to get that back, I don't care how crazy or evil she may be! 
Sorry, I had to look at all of her FB photos.
I know I have never met her and never will but goddamn she is hot! WELL DONE! You need to get that back, I don't care how crazy or evil she may be! 
1
Posted on 5/2/14 at 10:28 pm to ReauxlTide222
Algebra may just be the stupidest fricking subject ever invented. There is nothing in algebra that pertains to anything one does after the stupidest fricking subject is over. It is simply an exercise of mental masturbation to see who can play the game and who cannot.
Posted on 5/2/14 at 10:29 pm to ReauxlTide222
You could just plug in the choices if you can't figure out how to solve for X.
I don't have a pen and paper or I would help. Sorry.
I don't have a pen and paper or I would help. Sorry.
Posted on 5/2/14 at 10:30 pm to ReauxlTide222
Distribute the x through the revenue term. Move everything to one side.
You'll get something like 0.2x^2-20x+460.80=0
Quadratic Formula.
Done.
You'll get something like 0.2x^2-20x+460.80=0
Quadratic Formula.
Done.
Posted on 5/2/14 at 10:30 pm to ReauxlTide222
quote:
Wtf is wrong with me?!
Judging by your writing, I'd say the problem is that you're female
Posted on 5/2/14 at 10:31 pm to ReauxlTide222
-0.2x^2 + 20x - 460.8 = 0
Now apply the theory they taught you day 3 of class and solve.
Now apply the theory they taught you day 3 of class and solve.
This post was edited on 5/2/14 at 10:32 pm
Posted on 5/2/14 at 10:33 pm to ReauxlTide222
Why come to an LSU board to ask this when the human inbred genome was solved at Alabama
Posted on 5/2/14 at 10:34 pm to ReauxlTide222
C is the answer. Simplify it down 20X - .2X^2
You can either graph it or just substitute for X as it's multiple choice.
You can either graph it or just substitute for X as it's multiple choice.
Posted on 5/2/14 at 10:34 pm to lsu480
quote:
I sure wont. If you had called me when you and Kelsi got cupcakes at the store RIGHT NEXT TO MY HOUSE maybe I would have but now I refuse!
Those cupcakes are so good! I still have the app that updates when they have new flavors Posted on 5/2/14 at 10:36 pm to ReauxlTide222
Ya they really are the bomb! My friends ex owned it at the time and he would always boxes of them at his house!
Posted on 5/2/14 at 10:38 pm to ReauxlTide222
Sigh. Very well. I will answer it because you seem like a nice guy, and I have a good friend who gives me a ticket to LSU-Bama in Tuscaloosa every 2 years.
This can be boiled down to a simple quadratic equation.
Revenue = -0.2 x^2 + 41 x
Cost = 21 x
Profit = Revenue - Cost
Profit = -0.2 x^2 + 20 x
When is profit > 460.80 ?
It's when -0.2 x^2 + 20 x - 460.80 > 0.
Use the quadratic formula to solve for when -0.2 x^2 + 20 x - 460.80 = 0.
That happens at x = 36 and x = 64.
The derivative of the profit equation is -0.4x + 20, and is negative for 36 and positive for 64.
The second derivative of the profit is -0.4 for all values of x.
Therefore you know that you have an upside down parabola that only has positive values for profit (minus the 460.80) between values of 36 and 64.
Therefore the correct answer is C.
This can be boiled down to a simple quadratic equation.
Revenue = -0.2 x^2 + 41 x
Cost = 21 x
Profit = Revenue - Cost
Profit = -0.2 x^2 + 20 x
When is profit > 460.80 ?
It's when -0.2 x^2 + 20 x - 460.80 > 0.
Use the quadratic formula to solve for when -0.2 x^2 + 20 x - 460.80 = 0.
That happens at x = 36 and x = 64.
The derivative of the profit equation is -0.4x + 20, and is negative for 36 and positive for 64.
The second derivative of the profit is -0.4 for all values of x.
Therefore you know that you have an upside down parabola that only has positive values for profit (minus the 460.80) between values of 36 and 64.
Therefore the correct answer is C.
Posted on 5/2/14 at 10:38 pm to Doc Fenton
You just couldn't resist could you......
Posted on 5/2/14 at 10:39 pm to TigerPox
I admit I have a problem.
Posted on 5/2/14 at 10:40 pm to ReauxlTide222
x(41-0.2x)-21x = 460.8
-0.2x^2 + 41x - 21x - 460.8 = 0
-0.2x^2 + 20x - 460.8 = 0
Use your favorite method of calculating the quadratic equation:
Answer: 36 & 64
-0.2x^2 + 41x - 21x - 460.8 = 0
-0.2x^2 + 20x - 460.8 = 0
Use your favorite method of calculating the quadratic equation:
Answer: 36 & 64
This post was edited on 5/2/14 at 10:42 pm
Posted on 5/2/14 at 10:41 pm to ReauxlTide222
R = 41x - 0.2x^2
C = 21x
R - C >= 460.80
41x - 0.2x^2 - 21x = 460.80
205x - x^2 - 105x = 2304
x^2 + 100x + 2304 = 0
2304 = 9*256 = 3^2*2^8 = 3^2*2^2*2^6 = (3^2*2^2)*2^6 = 36*64
x^2 + 36x + 64x + 2304
x(x+36) + 64(x+36) = 0
(x+36)(x+64) = 0
So the issue I've gotten here is that the values that solve this equation are x = -36 and x = -64. I assume the answer is C and that I just screwed up my signs.
C = 21x
R - C >= 460.80
41x - 0.2x^2 - 21x = 460.80
205x - x^2 - 105x = 2304
x^2 + 100x + 2304 = 0
2304 = 9*256 = 3^2*2^8 = 3^2*2^2*2^6 = (3^2*2^2)*2^6 = 36*64
x^2 + 36x + 64x + 2304
x(x+36) + 64(x+36) = 0
(x+36)(x+64) = 0
So the issue I've gotten here is that the values that solve this equation are x = -36 and x = -64. I assume the answer is C and that I just screwed up my signs.
Posted on 5/2/14 at 10:41 pm to Doc Fenton
^------ what he said.
By he, I mean Doc.
By he, I mean Doc.
This post was edited on 5/2/14 at 10:43 pm
Posted on 5/2/14 at 10:41 pm to Doc Fenton
quote:
This can be boiled down to a simple quadratic equation.
Revenue = -0.2 x^2 + 41 x
Cost = 21 x
Profit = Revenue - Cost
Profit = -0.2 x^2 + 20 x
When is profit > 460.80 ?
It's when -0.2 x^2 + 20 x - 460.80 > 0.
Use the quadratic formula to solve for when -0.2 x^2 + 20 x - 460.80 = 0.
That happens at x = 36 and x = 64.
The derivative of the profit equation is -0.4x + 20, and is negative for 36 and positive for 64.
The second derivative of the profit is -0.4 for all values of x.
Therefore you know that you have an upside down parabola that only has positive values for profit (minus the 460.80) between values of 36 and 64.
Therefore the correct answer is C.
Ya...that is totally what I was gonna say!
Posted on 5/2/14 at 10:42 pm to StrangeBrew
quote:
Why come to an LSU board to ask this when the human inbred genome was solved at Alabama
Only response I got from TiderInsider was, "math? never heard of it."
Posted on 5/2/14 at 10:43 pm to lsu480
I just said C. Didn't say I had to show my work.
Posted on 5/2/14 at 10:45 pm to ReauxlTide222
quote:
Only response I got from TiderInsider was, "math? never heard of it."
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