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re: Let's discuss the Monty Hall problem (probabilities, odds)

Posted on 8/12/17 at 9:56 am to
Posted by shel311
McKinney, Texas
Member since Aug 2004
111136 posts
Posted on 8/12/17 at 9:56 am to
quote:

this is why i make money playing poker (made my return last night after almost a month off)

Right. I love poker but never got way into it. If you throw every emotion out the window and play strictly on the math(if you know the math obviously) you'll be successful in the long run playing at lower levels or random casino games(meant to say, not playing the pros)


This is essentially a math equation. I'd never know it without it being explained. BUt now that I do I know it's not a theory, it's a proven fact that switching gives you a 2in 3 chance of being correct.
This post was edited on 8/12/17 at 9:57 am
Posted by PrimeTime Money
Houston, Texas, USA
Member since Nov 2012
27324 posts
Posted on 8/12/17 at 9:57 am to
quote:

I dont buy that the odds don't change
You just told me that you understood the math.

That's obviously not the case.
Posted by shel311
McKinney, Texas
Member since Aug 2004
111136 posts
Posted on 8/12/17 at 9:57 am to
quote:

I dont buy that the odds don't change

Tell me where this is incorrect.

3 options, you choose door 1 each time, you switch every time:

1. Car is behind door 1, you switch you lose

2. Car is behind door 2, you switch you win

3. Car is behind door 3, you switch you win
Posted by SlowFlowPro
Simple Solutions to Complex Probs
Member since Jan 2004
423378 posts
Posted on 8/12/17 at 9:59 am to
actually playing by the math (as in GTO) is more required for playing against experts

but basic math and an understanding that donks want to gamble will print money long term. you just have to deal with variance and minimize bad runs/losses. i would add in "maximize wins" but i'm coming off a bad run and am playing like a pussy right now and don't want to false advertise

quote:

This is essentially a math equation. I'd never know it without it being explained. BUt now that I do I know it's not a theory, it's a proven fact that switching gives you a 2in 3 chance of being correct.

there used to be (probably still exist) websites that let you run simulations of this problem
Posted by Nado Jenkins83
Land of the Free
Member since Nov 2012
59753 posts
Posted on 8/12/17 at 10:00 am to
I understand the math

It's the perception of changing from 3 doors to 2

Posted by SlowFlowPro
Simple Solutions to Complex Probs
Member since Jan 2004
423378 posts
Posted on 8/12/17 at 10:00 am to
Monty Hall Sim

you can run it 1k times
Posted by shel311
McKinney, Texas
Member since Aug 2004
111136 posts
Posted on 8/12/17 at 10:01 am to
quote:

I understand the math


Do you? You said this 2 pages ago:

quote:

Yea and if you switch you have a 1/3 chance as it is only one door out of 3.
This post was edited on 8/12/17 at 10:03 am
Posted by LSUGrad9295
Baton Rouge
Member since May 2007
33550 posts
Posted on 8/12/17 at 10:02 am to
Fun fact of the day: Monty Hall is still alive and kicking. He is going to turn 96 in a couple weeks. His wife of 69 years passed away in June.
Posted by Nado Jenkins83
Land of the Free
Member since Nov 2012
59753 posts
Posted on 8/12/17 at 10:03 am to
If your still counting the opened door when you switch yes.

If it is eliminated then no
Posted by SlowFlowPro
Simple Solutions to Complex Probs
Member since Jan 2004
423378 posts
Posted on 8/12/17 at 10:03 am to
bro

go to the sim i just linked. spent like 20 minutes passively running it a few thousand times
Posted by PrimeTime Money
Houston, Texas, USA
Member since Nov 2012
27324 posts
Posted on 8/12/17 at 10:04 am to
quote:

I understand the math

It's the perception of changing from 3 doors to 2
You keep saying this, but if you understood the math this wouldn't be an issue for you.
Posted by Nado Jenkins83
Land of the Free
Member since Nov 2012
59753 posts
Posted on 8/12/17 at 10:04 am to
Nah. I'm good
Posted by shel311
McKinney, Texas
Member since Aug 2004
111136 posts
Posted on 8/12/17 at 10:04 am to
quote:

If your still counting the opened door when you switch yes.

If it is eliminated then no
Gonna post it again...

Tell me where this is incorrect.

3 options, you choose door 1 each time, you switch every time:

1. Car is behind door 1, you switch you lose

2. Car is behind door 2, you switch you win

3. Car is behind door 3, you switch you win
Posted by Martini
Near Athens
Member since Mar 2005
48861 posts
Posted on 8/12/17 at 10:07 am to
quote:



This.

If I switched and lost because my original pick was correct I'd give every nerd I saw for the rest of my life a swirlie.


What the frick is a swirlie?
Posted by PrimeTime Money
Houston, Texas, USA
Member since Nov 2012
27324 posts
Posted on 8/12/17 at 10:08 am to
Well then I guess you're done here. You don't wanna open your mind you just want to argue.
This post was edited on 8/12/17 at 10:10 am
Posted by SlowFlowPro
Simple Solutions to Complex Probs
Member since Jan 2004
423378 posts
Posted on 8/12/17 at 10:10 am to
quote:

Nah. I'm good

i'll do it for you
Posted by LSUBoo
Knoxville, TN
Member since Mar 2006
101930 posts
Posted on 8/12/17 at 11:11 am to
quote:

I understand the math

It's the perception of changing from 3 doors to 2


If you really understood the math, you wouldn't worry about the perception.


As an aside not to you, I haven't played poker in a while... I'd love to get a good home game going again.
Posted by TigrrrDad
Member since Oct 2016
7136 posts
Posted on 8/12/17 at 11:12 am to
quote:

Let's keep it easy and always pick door 1... keep in mind he can't show you door 1 (your pick) and he can't show you the car 1 2 3 stay switch C G G W L G C G L W G G C L W 2/3 odds if switch 1/3 odds if stay


But there is a goat behind door #3, so this leaves only the first two scenarios, which is 50/50.
Posted by TigrrrDad
Member since Oct 2016
7136 posts
Posted on 8/12/17 at 11:22 am to
quote:

Tell me where this is incorrect. 3 options, you choose door 1 each time, you switch every time: 1. Car is behind door 1, you switch you lose 2. Car is behind door 2, you switch you win 3. Car is behind door 3, you switch you win


Because the way the problem was stated, you picked door #1 and door #3 was opened, so the car is not behind door #3, leaving only the first two sçenarios, which shows the odds to be 50%.
If the problem is worded that you choose a door and the host opens a door to reveal a goat, it's a different scenario. That's not what the problems states as given in the OP.
This post was edited on 8/12/17 at 11:25 am
Posted by Sneaky__Sally
Member since Jul 2015
12364 posts
Posted on 8/12/17 at 11:23 am to
just go watch 21 they explain it there.

but it has to do with what i call relative probability.

ETA: Think of it this way - you pick your door for the prize. Then if someone said "i'll let you choose either to keep your door or to choose both of the other doors" which would you choose?

This is essentially what the host is doing by removing the incorrect door. While the new choice is essentially 50 / 50 - given what you know about the way the game is set up it is really 33% your door and 66% the other door since the other door has also taken on the probability of the door which the host has already revealed.

That is probably the best i can do without writing out a proof. Probability Theory and Discrete Mathematics is really fascinating - one of the courses i kept my textbook for.
This post was edited on 8/12/17 at 11:29 am
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