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How to setup a linear programming word problem constraint
Posted on 12/3/14 at 5:02 pm
Posted on 12/3/14 at 5:02 pm
I've been researching for 2 days. I've googled and read text book. I've set up the rest of the problem but am still getting stumped on this one part..
" No characters on map / in game = base of 121 FPS
To keep the app running above 30fps, that means there are only 91 fps that we can drop (121fps - 30fps = 91fps)
Adding only female characters causes a drop in 5 frames per second for every 10 characters added to the map
Adding only male characters causes a drop in 10 frames per second for each 10 characters added.
How would I set this up as an equation?
male = x female = y
I would hump a goat to find out this minute part of the whole word problem.
There is no answer as I have the rest of the variables. How would I set up this constraint?
:bow: :bow: :bow: :bow: :bow: :bow:
" No characters on map / in game = base of 121 FPS
To keep the app running above 30fps, that means there are only 91 fps that we can drop (121fps - 30fps = 91fps)
Adding only female characters causes a drop in 5 frames per second for every 10 characters added to the map
Adding only male characters causes a drop in 10 frames per second for each 10 characters added.
How would I set this up as an equation?
male = x female = y
I would hump a goat to find out this minute part of the whole word problem.
There is no answer as I have the rest of the variables. How would I set up this constraint?
:bow: :bow: :bow: :bow: :bow: :bow:
Posted on 12/3/14 at 5:06 pm to TigerDik86
y = -5 when x + y = 10z, where x = 0
x = -10 when x + y = 10z, where y = 0
x = -10 when x + y = 10z, where y = 0
This post was edited on 12/3/14 at 5:10 pm
Posted on 12/3/14 at 5:07 pm to TigerDik86
Constant-time technology and access points have garnered great interest from both futurists and physicists in the last several years. After years of extensive research into superpages, we confirm the appropriate unification of 128-bit architectures and checksums.
Posted on 12/3/14 at 5:11 pm to KosmoCramer
could it be -10x + -5y <= 91
Posted on 12/3/14 at 5:22 pm to TigerDik86
If you drop 5 frames for 10 females, the total frames dropped for females is 5y/10.
For males it is 10x/10.
So,
5y/10 + 10x/10 <= 91, or
y/2 + x <= 91
For males it is 10x/10.
So,
5y/10 + 10x/10 <= 91, or
y/2 + x <= 91
Posted on 12/3/14 at 6:34 pm to ChEgrad
quote:
ChEgrad
I would make love to your bum
Posted on 12/3/14 at 6:35 pm to gizmoflak
actually, this is a single step in a larger equation.
Imagine if calculus was a whore and physics was a drifter. linear programming is their bastard child.
Imagine if calculus was a whore and physics was a drifter. linear programming is their bastard child.
Posted on 12/3/14 at 6:43 pm to TigerDik86
I would do it like this:
-5ps/10y = -0.5fps/y, so each woman reduces fps by 0.5. apply same concept to men --> reduce 1 fps per man
subtract both values from the starting level of 121
Must have equation = 30
121 - (0.5y) - (x) (> or =) 30
Simplify by subtracting 121 from both sides
- (0.5y) - (x) (> or =) 30 - 121
-0.5y - x (> or =) - 91
or 0.5y + x (< or =) 91
EDIT: reading skills, changed my equations appropriately
-5ps/10y = -0.5fps/y, so each woman reduces fps by 0.5. apply same concept to men --> reduce 1 fps per man
subtract both values from the starting level of 121
Must have equation = 30
121 - (0.5y) - (x) (> or =) 30
Simplify by subtracting 121 from both sides
- (0.5y) - (x) (> or =) 30 - 121
-0.5y - x (> or =) - 91
or 0.5y + x (< or =) 91
EDIT: reading skills, changed my equations appropriately
This post was edited on 12/3/14 at 6:50 pm
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