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re: High School Math question
Posted on 11/27/16 at 6:10 pm to Bloodworth
Posted on 11/27/16 at 6:10 pm to Bloodworth
quote:
Round your answer to the nearest tenth.
Thanks for the tip... considering the multiple choice answers.
Posted on 11/27/16 at 6:12 pm to Bloodworth
Posted on 11/27/16 at 6:13 pm to Bloodworth
quote:
the math pros on this board.
This is where your plan went wrong.
Posted on 11/27/16 at 6:18 pm to Bloodworth
quote:
m?B = 45
You need to tell us which two sides this angle separates. Calling it "angle B" means nothing.
Posted on 11/27/16 at 6:19 pm to Bloodworth
quote:
No... My daughter is struggling with this question and was hoping for some help from the math pros on this board.
Seriously, what I said.
IF RIGHT TRIANGLE
Sin (angle) = opp/hyp
Cos (Angle) = adjacent/hyp
Tan (angle) = opposite/adjacent
IF NOT RIGHT TRIANGLE USE ONE OF THESE EQUATIONS
This post was edited on 11/27/16 at 6:20 pm
Posted on 11/27/16 at 7:30 pm to Bloodworth
It's not a right triangle because the angle is 45. If it were it would be an isolese and 24^2+24^2 doesn't equal 30^2. Use b^2=a^2+c^2-2acCosB. Solve for b.
Posted on 11/27/16 at 7:34 pm to Bloodworth
Use law of cosines
b^2 = a^2 + c^2 -2ac*cos B
b^2 = a^2 + c^2 -2ac*cos B
Posted on 11/27/16 at 7:38 pm to Bloodworth
b^2 = 576 + 900 - 1440 * (sqrt 2)/2
Now just solve but be carefully with order of operations
Now just solve but be carefully with order of operations
Posted on 11/27/16 at 7:42 pm to Bloodworth
Nm, someone above explained perfectly
This post was edited on 11/27/16 at 7:46 pm
Posted on 11/27/16 at 7:43 pm to Bloodworth
Jfc, people ... all these answers and not one of you degenerates asked for pics? ...
Posted on 11/27/16 at 8:01 pm to tiderider
Change your choice to the other door
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