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Message
re: Let's Overanalyze "Home Alone" and "Home Alone 2"
Posted on 12/7/11 at 1:52 pm to CocomoLSU
Posted on 12/7/11 at 1:52 pm to CocomoLSU
Somebody correct me on my work if I'm wrong and I don't want to turn this thread into a math course, but we could use the equation that takes account for speed due to gravity.
That is v^2=u^2+2as
where v=velocity at the bottom
u=starting velocity
a=acceleration, gravity 32.2 ft/s
s=starting height
So with your numbers you get
v^2=0+2(32.2)(40)
v^2=2576
v=50.75 ft/s
that converts to 34.6 mph
Damn...
That is v^2=u^2+2as
where v=velocity at the bottom
u=starting velocity
a=acceleration, gravity 32.2 ft/s
s=starting height
So with your numbers you get
v^2=0+2(32.2)(40)
v^2=2576
v=50.75 ft/s
that converts to 34.6 mph
Damn...
Posted on 12/7/11 at 1:54 pm to Josh Fenderman
Works for me. I haven't seen physics since high school, and I wasn't crazy about it then anyway. So any attempt to try to get it exactly correct would've been hard and embarassing for me. .
Posted on 12/8/11 at 10:02 am to Josh Fenderman
quote:
Somebody correct me on my work if I'm wrong and I don't want to turn this thread into a math course, but we could use the equation that takes account for speed due to gravity.
Why shouldn't it? This is an over analysis thread, and overanalyzing often involves math. I hope you do one for the iron, since I think that would have certainly cracked Marv's skull open as well.
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