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re: Can this 747 take off?
Posted on 4/11/24 at 9:50 pm to Power-Dome
Posted on 4/11/24 at 9:50 pm to Power-Dome
It doesn’t imply that, you interpreted it that way. The question is from world of engineering and it says the belt is designed to match the speed.
Engineering answer is it’s not possible to design it mathematically. What happens is the backwards speed of the belt is offset by the forward speed of the wheels, as designed…As soon as the engines add an independent source of forward motion the belt will perpetually be behind by that number.
You increase the belt by 1000 mph the wheels go 1000 mph faster so they cancel each other out. You’re left with only the forward thrust and the plane takes off as normal.
Engineering answer is it’s not possible to design it mathematically. What happens is the backwards speed of the belt is offset by the forward speed of the wheels, as designed…As soon as the engines add an independent source of forward motion the belt will perpetually be behind by that number.
You increase the belt by 1000 mph the wheels go 1000 mph faster so they cancel each other out. You’re left with only the forward thrust and the plane takes off as normal.
This post was edited on 4/11/24 at 9:52 pm
3
Posted on 4/11/24 at 9:53 pm to PhysicsGuy
quote:si the wheels be moving faster than the belt
As soon as the engines add an independent source of forward motion the belt will perpetually be behind by that number.
Posted on 4/11/24 at 10:00 pm to PhysicsGuy
quote:
The conveyor belt is designed to exactly match the speed of the wheels, moving in the opposite direction...
I looked at it again, and think if everyone agreed About this statement. We’d have agreement.
If “speed”= wheel rotation, the plane will move forward until lift is achieved regardless whether the windmill hit infinity.
If speed= objective placement between the treadmill and the landing gear, then you achieve the scenario of a perpetually stationary object.
Posted on 4/11/24 at 10:01 pm to PhysicsGuy
My interpretation in this rolling-friction-counter-force model was that the tread goes fast enough that the center axle as zero velocity. The vectors at the top and bottom of the wheel would be equal and opposite.
I posed a thought experiment earlier with a small toy plane with no engines on needing to be held in place to keep from falling off the back of a running household treadmill. Obviously there is a force transmitted tangentially to a free rolling object to send it off the back of a treadmill, no? And could there not theoretically be a tremendously fast treadmill that could produce enough of this tangential force to counteract the thrust?
I posed a thought experiment earlier with a small toy plane with no engines on needing to be held in place to keep from falling off the back of a running household treadmill. Obviously there is a force transmitted tangentially to a free rolling object to send it off the back of a treadmill, no? And could there not theoretically be a tremendously fast treadmill that could produce enough of this tangential force to counteract the thrust?
This post was edited on 4/11/24 at 10:03 pm
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