Uncaught third strike question

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but if there's no one base, why throw to 1st?

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Not understanding your question

I'm guessing a rule explanation is what is needed here. On a dropped third strike the ball must be thrown to first in order to complete the put out. This only counts if first base is unoccupied at the point of the pitch or occupied with two outs. With bases loaded the rule only applies with 2 outs. Therefore by dropping the ball and stepping on home plate for the force you complete the put out on the force at home and end the inning. Remember, you only have to complete the put out on a dropped third strike 1) if first base is unoccupied or 2)it is occupied but there are 2 outs.

The batter is automatically out with a runner on 1st and less than 2 outs (to prevent unfair double plays). Otherwise, the batter becomes a runner and can attempt to reach first base, hence the need for a throw.

Quit messing with the integrity of the game. Guess you want to remove all umpires and just the cameras call strikes and balls?

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CheerWhine

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The batter is automatically out with a runner on 1st and less than 2 outs (to prevent unfair double plays). Otherwise, the batter becomes a runner and can attempt to reach first base, hence the need for a throw

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Thanks

Not trying to mess with integrity of the game, just wanted a better understanding of the reasoning behind it

You just like balls and cameras