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Started By
Message
Brain Teaser
Posted on 2/6/15 at 2:32 pm
Posted on 2/6/15 at 2:32 pm
(no message)
This post was edited on 2/6/15 at 9:48 pm
19
Posted on 2/6/15 at 2:33 pm to ike221
So....
You forgot the combination, huh?
You forgot the combination, huh?
Posted on 2/6/15 at 2:35 pm to ike221
Posted on 2/6/15 at 2:36 pm to ike221
Call pop a lock or bust the window
Posted on 2/6/15 at 2:36 pm to ike221
Solved. 4-9-0-3-6
Eta: u gone get raped.
Eta: u gone get raped.
This post was edited on 2/6/15 at 2:43 pm
Posted on 2/6/15 at 2:40 pm to ike221
Why didn't you just use your birthday or address? 
Posted on 2/6/15 at 2:41 pm to RoIITide
Posted on 2/6/15 at 2:43 pm to Mahootney
Pretty easy since you didn't repeat numbers. You go from 30240 possible combinations to just 252.
Find perfect squares. Find palindromes. Add the largest digits. Eliminate all palindromes above the max.
That leaves just 4 squares and only one possible palindrome. Pretty simple stuff.
Find perfect squares. Find palindromes. Add the largest digits. Eliminate all palindromes above the max.
That leaves just 4 squares and only one possible palindrome. Pretty simple stuff.
This post was edited on 2/6/15 at 2:47 pm
Posted on 2/6/15 at 2:49 pm to ike221
nope
This post was edited on 2/6/15 at 2:51 pm
Posted on 2/6/15 at 2:52 pm to ike221
696969
Posted on 2/6/15 at 2:57 pm to ike221
7
Posted on 2/6/15 at 2:58 pm to Mahootney
Not so easy if you forget to use 0
Posted on 2/6/15 at 2:58 pm to dyslexic
Edit
Posted on 2/6/15 at 2:59 pm to ike221
Posted on 2/6/15 at 3:02 pm to ike221
You don't bury survivors.
Posted on 2/6/15 at 3:05 pm to ike221
Tree fiddy
288
288
Posted on 2/6/15 at 3:06 pm to link
quote:this part is confusing. a palindrome like how (8+1)+0+(4+9)=22, or how 64+1+36=101?
If the five digits are arranged to form all possible 5 digit combinations. The sum of all the combinations are a palindrome.
Posted on 2/6/15 at 3:06 pm to warlock1974
True. But 3,6,4,&9 add to 22.
And 11 is too small and 33 is too big to work with adding digits of squares without repeating.
So, the squares stipulation leaves you with 25, 36, 49,& 64. The sum of unique digits leaves 16,17,20, and 22.
With the middle digit being the smallest, (ie 1 or 0) only 22 gets you to a palindrome.
And 11 is too small and 33 is too big to work with adding digits of squares without repeating.
So, the squares stipulation leaves you with 25, 36, 49,& 64. The sum of unique digits leaves 16,17,20, and 22.
With the middle digit being the smallest, (ie 1 or 0) only 22 gets you to a palindrome.
Posted on 2/6/15 at 3:08 pm to link
quote:i assumed individual number addition.
quote:
If the five digits are arranged to form all possible 5 digit combinations. The sum of all the combinations are a palindrome.
this part is confusing. a palindrome like how (8+1)+0+(4+9)=22, or how 64+1+36=101?
Posted on 2/6/15 at 3:13 pm to Mahootney
before he added the divisible by 3 rule, 49036 and 81049 both worked. now nothing works, and i need some closure.
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