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Posted by
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You have 8 apparently identical balls, but one is heavier than the others
Posted by Masterag on 10/16/17 at 7:30 pm113
and you have a balance scale with which to weigh the balls
What is the fewest number of times you can use the scale to determine which is the heavier and how do you do it?
What is the fewest number of times you can use the scale to determine which is the heavier and how do you do it?
re: You have 8 apparently identical balls, but one is heavier than the othersPosted by Brosef Stalin on 10/16/17 at 7:30 pm to Masterag
I've only got two balls. Why do you have 8?
re: You have 8 apparently identical balls, but one is heavier than the othersPosted by StealthCalais11 on 10/16/17 at 7:32 pm to Masterag
quote:
You have 8 apparently identical balls, but one is heavier than the others
You should probably get that checked out
re: You have 8 apparently identical balls, but one is heavier than the othersPosted by East Coast Band on 10/16/17 at 7:32 pm to Masterag
Of course an aggie fan would be interested in balls.
This post was edited on 10/16 at 7:33 pm
re: You have 8 apparently identical balls, but one is heavier than the othersPosted by razorbackfan4life on 10/16/17 at 7:32 pm to Masterag
3
1 if you guess the right ball to begin with and use it to outweigh another
3 if you don’t start out by a lucky guess
Initial weigh in (4-4)
Split heavier side into 2-2
Split still heavier side into 1-1 to determine winner
ETA: I concede to the person who said/explained 2 below.
3 if you don’t start out by a lucky guess
Initial weigh in (4-4)
Split heavier side into 2-2
Split still heavier side into 1-1 to determine winner
ETA: I concede to the person who said/explained 2 below.
This post was edited on 10/17 at 8:51 am
re: You have 8 apparently identical balls, but one is heavier than the othersPosted by DavidTheGnome on 10/16/17 at 7:33 pm to Masterag
Four?
4 > 4
3 > 3
2 > 2
1 > 1 found the heaviest, probably not the answer though
Edit: I was close
4 > 4
3 > 3
2 > 2
1 > 1 found the heaviest, probably not the answer though
Edit: I was close
This post was edited on 10/16 at 7:34 pm
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re: You have 8 apparently identical balls, but one is heavier than the othersPosted by PrivatePublic on 10/16/17 at 7:34 pm to Masterag
The correct answer is 2 times.
3 x 3.
If they are equal, then the heavier ball is in the remaining 2, put them side by side.
If they are not equal, take 2 from the heavier side and put them side by side. If equal, heavier ball is the remaining one. Otherwise, heavier ball is obvious.
Answer = 2.
3 x 3.
If they are equal, then the heavier ball is in the remaining 2, put them side by side.
If they are not equal, take 2 from the heavier side and put them side by side. If equal, heavier ball is the remaining one. Otherwise, heavier ball is obvious.
Answer = 2.
re: You have 8 apparently identical balls, but one is heavier than the othersPosted by OysterPoBoy on 10/16/17 at 7:34 pm to Masterag
Just drop them all from a ladder and see which one hits first.
re: You have 8 apparently identical balls, but one is heavier than the othersPosted by Masterag on 10/16/17 at 7:35 pm to PrivatePublic
quote:
PrivatePublic
re: You have 8 apparently identical balls, but one is heavier than the othersPosted by TheWalrus on 10/16/17 at 7:39 pm to PrivatePublic
Damnit
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